After searching for a while for a solution for this I've e up with none. What I'm trying to do is create a diagonal border on the first li element's top left corner.. I tried using a solution that involved the background property but it doesn't give me quite what I want. Also it doesn't allow any manipulation of the colors which will be needed later on.

The light blue color should be a border that gets cut (and not a background that gets cut) and the dark grey should be the background of the li.

How can I achieve this via CSS? A JS/Jquery solution would work as well.

EDIT: After seeing a lot of misinterpreted answers to my question I'll clarify it a bit:

The left image is what I have now, the right image should be the result.

.cal-scheme {
    width: 100%;

    li {
        width: calc(100% / 6);
        height: 150px;
        margin: 0;
        padding: 0;
        border: $thin-blue;
        box-sizing: border-box;
        float: left;

        &:first-child {
            background: linear-gradient(135deg, transparent 20px, $light-blue 0);
            border: 0;
        }
    }
}

After searching for a while for a solution for this I've e up with none. What I'm trying to do is create a diagonal border on the first li element's top left corner.. I tried using a solution that involved the background property but it doesn't give me quite what I want. Also it doesn't allow any manipulation of the colors which will be needed later on.

The light blue color should be a border that gets cut (and not a background that gets cut) and the dark grey should be the background of the li.

How can I achieve this via CSS? A JS/Jquery solution would work as well.

EDIT: After seeing a lot of misinterpreted answers to my question I'll clarify it a bit:

The left image is what I have now, the right image should be the result.

.cal-scheme {
    width: 100%;

    li {
        width: calc(100% / 6);
        height: 150px;
        margin: 0;
        padding: 0;
        border: $thin-blue;
        box-sizing: border-box;
        float: left;

        &:first-child {
            background: linear-gradient(135deg, transparent 20px, $light-blue 0);
            border: 0;
        }
    }
}

• javascript
• jquery
• css

• How is Your border (lightblue) inside background (darkgrey)? – Bogdan Kuštan Commented Jan 3, 2015 at 11:11
• @BogdanKuštan It's not. I made the background light blue so you could see the problem since the background is dark grey. – Chrillewoodz Commented Jan 3, 2015 at 11:13
• 1 This isn't possible through border-radius just yet, but a proposed enhancement to this property will allow you to do exactly what you're looking for (search for "css corner shape"). In the meantime, applying this effect to a border will be somewhat nontrivial. There are a number of questions about chamfering a borderless background this way, with a solution demonstrated in Bogdan Kuštan's answer, but I'm not sure if any exist for borders. – BoltClock Commented Jan 3, 2015 at 11:24
• @Chrillewoodz: I see you have already accepted an answer. Here is another approach using pseudo-elements and border-image (lesser browser support). I will add as answer if you wish. – Harry Commented Jan 3, 2015 at 12:34
• @Harry I tried modifying your fiddle but it doesn't appear to be working unless you have a large border. Correct? – Chrillewoodz Commented Jan 3, 2015 at 12:38

2 Answers 2

If I understand question, You need something like this

HTML:

<ul>
    <li></li>
    <li></li>
    <li></li>
    <li></li>
    <li></li>
    <li></li>
    <li></li>
</ul>

CSS:

body {
    background: darkgrey;
}
li {
    display: block;
    list-style: none;
    width: 200px;
    height: 50px;
    background: lightblue;
    position: relative;
    border: 10px solid lightblue;
    margin-top: 5px;
}

li:first-child:after {
    content: '';
    display: block;
    width: 0;
    height: 0;
    border: 15px solid transparent;
    border-right-color: darkgrey;
    position: absolute;
    top: -15px;
    left: -15px;
    transform: rotate(45deg);
}

UPDATE:

You can't achieve with border-radius. Just using css shapes, or hacks like this updated fiddle

HTML:

<ul>
    <li></li>
    <li></li>
    <li></li>
    <li></li>
    <li></li>
    <li></li>
    <li></li>
</ul>

CSS:

body {
    background: darkgrey;
}
li {
    display: block;
    list-style: none;
    width: 200px;
    height: 50px;
    background: darkgrey;
    position: relative;
    border: 2px solid lightblue;
    margin-top: 5px;
}

li:first-child:after {
    content: '';
    display: block;
    width: 30px;
    height: 30px;
    background: darkgrey;
    border-right: 2px solid lightblue;
    position: absolute;
    top: -17px;
    left: -17px;
    transform: rotate(45deg);
}

How about achieving that like this? without border-radius property WORKING FIDDLE

Also have look at The Shapes of CSS on css-tricks.

HTML

<div class="square">
    <div class="cut-fold"></div>
</div>

CSS

    body {
    background: #2D2D2D;
}
.square {
    background: #5E9EE8;
    position: relative;
    width: 300px;
    height: 300px;
}
.cut-fold {
    background: #2d2d2d;
    height: 75px;
    position: absolute;
    top: -34px;
    transform: rotate(45deg);
    width: 30px;
}