I am looking for jQuery solution to detect mouseup outside the window. That is, after the mouse has been downed inside the window, dragged outside while still down, and then released outside, is when the event should fire.

I tried document.mouseup = function() {}, it didn't help. I tried to follow the example here, but couldn't properly understand it (I even left a ment asking for help, but no help yet..:( )

I am looking for jQuery solution to detect mouseup outside the window. That is, after the mouse has been downed inside the window, dragged outside while still down, and then released outside, is when the event should fire.

I tried document.mouseup = function() {}, it didn't help. I tried to follow the example here, but couldn't properly understand it (I even left a ment asking for help, but no help yet..:( )

• javascript
• jquery

• 4 I believe it should be document.onmouseup – Fabrício Matté Commented Feb 16, 2013 at 16:38
• Yeah yeah, I mean that actually...:D – NedStarkOfWinterfell Commented Feb 16, 2013 at 17:09

1 Answer 1

I have a website that uses this event and it works as you described:

$(window).on('mouseup', function(){
   //your code here
});

Note: only tested in jQuery 1.8.3, but it should work in 1.9

jsFiddle confirms. Works in jQuery 1.9.1 and 2 beta: http://jsfiddle/udRNx/1/

In case you didn't know, this piece of code must be placed in either $(document).ready(fn) or $(window).onload(fn).