I have a nested object and I want to flatten/map it into a single-layered, table-like object.

[{
    a: 1,
    b: 2,
    c: [{
        x: 10,
        y: 20
    }, {
        x: 30,
        y: 40
    }]
}, {
    a: 3,
    b: 4,
    c: [{
        x: 50,
        y: 60
    }, {
        x: 70,
        y: 80
    }]
}]

From that, I want to get something like this:

[{
    a: 1,
    b: 2,
    x: 10,
    y: 20
}, {
    a: 1,
    b: 2,
    x: 30,
    y: 40
}, {
    a: 3,
    b: 4,
    x: 50,
    y: 60
}, {
    a: 3,
    b: 4,
    x: 70,
    y: 80
}]

Sure, I could simply iterate over the object with two for loops and put the result info a separate array, but I wonder, if there is a simpler solution. I already tried to play around with flatMap. It works, if I only want the c portion of my nested object, but I don't know how to map a and b to this object.

As some of you asked for some working code, this should do it (untested):

let result = [];

for (const outer of myObj)
  for (const inner of outer.c)
    result.push({a: outer.a, b: outer.b, x: inner.x, y: inner.y});

The question is, if there is a functional one-liner or even another, better approach. In reality, my object consists of four layers and the nested for loops bee messy quite fast.

I have a nested object and I want to flatten/map it into a single-layered, table-like object.

[{
    a: 1,
    b: 2,
    c: [{
        x: 10,
        y: 20
    }, {
        x: 30,
        y: 40
    }]
}, {
    a: 3,
    b: 4,
    c: [{
        x: 50,
        y: 60
    }, {
        x: 70,
        y: 80
    }]
}]

From that, I want to get something like this:

[{
    a: 1,
    b: 2,
    x: 10,
    y: 20
}, {
    a: 1,
    b: 2,
    x: 30,
    y: 40
}, {
    a: 3,
    b: 4,
    x: 50,
    y: 60
}, {
    a: 3,
    b: 4,
    x: 70,
    y: 80
}]

Sure, I could simply iterate over the object with two for loops and put the result info a separate array, but I wonder, if there is a simpler solution. I already tried to play around with flatMap. It works, if I only want the c portion of my nested object, but I don't know how to map a and b to this object.

As some of you asked for some working code, this should do it (untested):

let result = [];

for (const outer of myObj)
  for (const inner of outer.c)
    result.push({a: outer.a, b: outer.b, x: inner.x, y: inner.y});

The question is, if there is a functional one-liner or even another, better approach. In reality, my object consists of four layers and the nested for loops bee messy quite fast.

• javascript
• flatmap

• This might better be suited for codereview.stackexchange. if you actually don't have any problem – Brewal Commented Mar 11, 2020 at 13:32
• 1 Your not really flattering here, because you would have duplicate x & y's if it was. Also is this structure always this way, what if the {x,y} had another sub array, would this multiple out even more. – Keith Commented Mar 11, 2020 at 13:33
• 1 @Brewal Definitely not a question for codereview. – Teemu Commented Mar 11, 2020 at 13:33
• 1 @Brewal But they're fixing existing and working code at codereview, when not having code at all is even harder to answer there than here. – Teemu Commented Mar 11, 2020 at 13:37
• 1 @Teemu I assumed there was actually already a working solution. – Brewal Commented Mar 11, 2020 at 13:48

5 Answers 5

You may use flatMap method alongwith map on property 'c':

var input = [{ a: 1, b: 2, c: [{ x: 10, y: 20 }, { x: 30, y: 40 }] }, { a: 3, b: 4, c: [{ x: 50, y: 60 }, { x: 70, y: 80 }] }];

const output = input.flatMap(obj =>
  obj.c.map(arr => ({a: obj.a, b: obj.b, x: arr.x, y: arr.y}))
);

console.log(output);

Ideally a solution would require something to tell how far down to start classing the object as been a full object, a simple solution is just to pass the level you want. If you don't want to pass the level, you could do a check and if none of the properties have array's, then you would class this as a plete record, but of course that logic is something you would need to confirm.

If you want a generic version that works with multiple levels were you pass the level & using recursion you could do something like this ->

const a=[{a:1,b:2,c:[{x:10,y:20},{x:30,y:40}]},{a:3,b:4,c:[{x:50,y:60},{x:70,y:80}]}];


function flattern(a, lvl) {
  const r = [];
  function flat(a, l, o) {
    for (const aa of a) {
      o = {...o};
      for (const [k, v] of Object.entries(aa)) {
        if (Array.isArray(v) && l < lvl) flat(v, l + 1, o);
        else o[k] = v;
      }
      if (l === lvl) r.push(o);
    }
  }
  flat(a, 1);
  return r;
}

console.log(flattern(a, 2));
//console.log(flattern(a, 1));

A flatMap solution would look like this:

const result = myObj.flatMap(outer =>
  outer.c.map(inner =>
    ({a: outer.a, b: outer.b, x: inner.x, y: inner.y})
  )
);

Of course, if your object has multiple layers, not just two, and possibly even multiple or unknown properties that have such a nesting, you should try to implement a recursive solution. Or an iterative one, where you loop over an array of property names (for your example case, ["c"]) and apply the flattening level by level.

One of the solution using reduce is:

const list = [{
    a: 1,
    b: 2,
    c: [{
        x: 10,
        y: 20
    }, {
        x: 30,
        y: 40
    }]
}, {
    a: 3,
    b: 4,
    c: [{
        x: 50,
        y: 60
    }, {
        x: 70,
        y: 80
    }]
}]

const flatten = (arr) => {
  return arr.reduce((flattened, item) => {
    return [
      ...flattened,
      ...item.c.reduce((flattenedItem, i) => {
        return [
          ...flattenedItem,
          {
            a: item.a,
            b: item.b,
            x: i.x,
            y: i.y
          }
        ]
      }, [])
    ]
  }, [])
}

console.log(flatten(list));

Using two reducers to flatten your structure

const input = [{
  a: 1,
  b: 2,
  c: [{
    x: 10,
    y: 20
  }, {
    x: 30,
    y: 40
  }]
}, {
  a: 3,
  b: 4,
  c: [{
    x: 50,
    y: 60
  }, {
    x: 70,
    y: 80
  }]
}]

const result = input.reduce((acc_0, x) => {
  return [...acc_0, ...x.c.reduce((acc_1, y) => {
    const obj = {
      a: x.a,
      b: x.b,
      x: y.x,
      y: y.y
    }
    acc_1.push(obj);
    return acc_1;
  }, [])]
}, []);

console.log(result)