最新消息:雨落星辰是一个专注网站SEO优化、网站SEO诊断、搜索引擎研究、网络营销推广、网站策划运营及站长类的自媒体原创博客

How to get first specific value in json object using javascript - Stack Overflow

programmeradmin0浏览0评论

I like to know how i can get first specific value in a json like

$.each(data, function(i, val){
    console.log(val.name);
});

sample output of above code is like this

John
Mary
Kite

but i like to get only first value like this

John

I like to know how i can get first specific value in a json like

$.each(data, function(i, val){
    console.log(val.name);
});

sample output of above code is like this

John
Mary
Kite

but i like to get only first value like this

John
Share Improve this question asked Jan 23, 2014 at 2:07 jttoratejttorate 611 gold badge1 silver badge9 bronze badges 4
  • 1 What data type is data? Object or array – scrblnrd3 Commented Jan 23, 2014 at 2:09
  • If it's not an Array, then there is no "first" since objects are unordered. – cookie monster Commented Jan 23, 2014 at 2:10
  • You may be able to get the first that is defined in the original JSON string if you use JSON.parse() and pass it a "reviver" function. I think it'll give you the properties you encounter in order, though it'll traverse into a nested object before giving you the key for that object. – cookie monster Commented Jan 23, 2014 at 2:18
  • ...other than that, if all you need is the first property of the object, then you could parse it yourself just up to that point, and then JSON.parse() it, and use the property you found to grab the first., – cookie monster Commented Jan 23, 2014 at 2:22
Add a ment  | 

3 Answers 3

Reset to default 5

If data is an array, you can do

name=data[0].name

If it's an object, it's slightly more plicated

name=data[Object.keys(data)[0]].name;

Keep in mind that object keys aren't really sorted in any particular order

It depends on the structure of the json object but it should look like this:

data[0].name

If you return false from the iteration function, $.each() terminates the loop. So you can simply return false the first time:

$.each(data, function(i, val){
    console.log(val.name);
    return false;
});

Since object elements don't have any inherent order, there's no guarantee this will print a specific name. It will just pick one of the names arbitrarily.

发布评论

评论列表(0)

  1. 暂无评论