i have an issue. How can i clone an existing div with jquery?
[Image]1
<div class="modal-body">
<div class="row">
<div class="col-md-5 text-center">
<b>Número Factura</b>
<input type="number" class="form-control" id="numero"><br/>
</div>
<div class="col-md-2 text-center">
-o-
</div>
<div class="col-md-5 text-center">
<b>Número Remisión</b>
<input type="number" class="form-control" id="remision"><br/>
</div>
<div class="col-md-12">
<b>NIT:</b>
<?php $consulta = mysqli_query($conexion, "SELECT * FROM proveedores");
$resultado = mysqli_fetch_all($consulta, MYSQLI_ASSOC); ?>
<select class="form-control" id="proveedor">
<?php foreach($resultado as $r): ?>
<option value="<?php echo $r['nit']; ?>"><?php echo $r['nombre']; ?></option>
<?php endforeach; ?>
</select><br/>
</div>
<div class="col-md-2">
<input type="number" class="form-control" id="productos" value="1">
</div>
<div class="col-md-2">
<button type="button" class="btn btn-success agregar_producto" name="agregar_producto">
<i class="fas fa-user-plus" style="color: white"></i>
</button>
</div>
</div>
<br/>
<div id="contenido" class="row text-center">
<div class="col-md-4">
<b>Producto</b>
<?php $consulta = mysqli_query($conexion, "SELECT * FROM productos");
$resultado = mysqli_fetch_all($consulta, MYSQLI_ASSOC); ?>
<select class="form-control" id="producto">
<?php foreach($resultado as $r): ?>
<option value="<?php echo $r['id']; ?>"><?php echo $r['descripcion']; ?></option>
<?php endforeach; ?>
</select><br/>
</div>
<div class="col-md-4">
<b>Cantidad</b>
<input type="number" class="form-control" id="cantidad"><br/>
</div>
<div class="col-md-4">
<b>Precio</b>
<input type="number" class="form-control" id="precio"><br/>
</div>
</div>
</div>
<div class="modal-footer">
<button type="button" class="btn btn-success crear" name="crear">Agregar Factura</button>
<button type="button" class="btn btn-secondary" data-dismiss="modal">Regresar</button>
</div>
I need to clone the div with id="contenido" when someone press the button with class="agregar_producto".
How can i solve it? [Example]2
Is it possible? i need only an example to solve my problem. Thx you! <3
EDIT: If a clone this inputs how can i change ids/class to this inputs?
i have an issue. How can i clone an existing div with jquery?
[Image]1
<div class="modal-body">
<div class="row">
<div class="col-md-5 text-center">
<b>Número Factura</b>
<input type="number" class="form-control" id="numero"><br/>
</div>
<div class="col-md-2 text-center">
-o-
</div>
<div class="col-md-5 text-center">
<b>Número Remisión</b>
<input type="number" class="form-control" id="remision"><br/>
</div>
<div class="col-md-12">
<b>NIT:</b>
<?php $consulta = mysqli_query($conexion, "SELECT * FROM proveedores");
$resultado = mysqli_fetch_all($consulta, MYSQLI_ASSOC); ?>
<select class="form-control" id="proveedor">
<?php foreach($resultado as $r): ?>
<option value="<?php echo $r['nit']; ?>"><?php echo $r['nombre']; ?></option>
<?php endforeach; ?>
</select><br/>
</div>
<div class="col-md-2">
<input type="number" class="form-control" id="productos" value="1">
</div>
<div class="col-md-2">
<button type="button" class="btn btn-success agregar_producto" name="agregar_producto">
<i class="fas fa-user-plus" style="color: white"></i>
</button>
</div>
</div>
<br/>
<div id="contenido" class="row text-center">
<div class="col-md-4">
<b>Producto</b>
<?php $consulta = mysqli_query($conexion, "SELECT * FROM productos");
$resultado = mysqli_fetch_all($consulta, MYSQLI_ASSOC); ?>
<select class="form-control" id="producto">
<?php foreach($resultado as $r): ?>
<option value="<?php echo $r['id']; ?>"><?php echo $r['descripcion']; ?></option>
<?php endforeach; ?>
</select><br/>
</div>
<div class="col-md-4">
<b>Cantidad</b>
<input type="number" class="form-control" id="cantidad"><br/>
</div>
<div class="col-md-4">
<b>Precio</b>
<input type="number" class="form-control" id="precio"><br/>
</div>
</div>
</div>
<div class="modal-footer">
<button type="button" class="btn btn-success crear" name="crear">Agregar Factura</button>
<button type="button" class="btn btn-secondary" data-dismiss="modal">Regresar</button>
</div>
I need to clone the div with id="contenido" when someone press the button with class="agregar_producto".
How can i solve it? [Example]2
Is it possible? i need only an example to solve my problem. Thx you! <3
EDIT: If a clone this inputs how can i change ids/class to this inputs?
Share Improve this question edited Apr 26, 2018 at 6:56 Death-is-the-real-truth 72.3k10 gold badges57 silver badges104 bronze badges asked Apr 26, 2018 at 6:05 Juan MolinaJuan Molina 651 silver badge8 bronze badges 5- How about a google search? Stumbled upon this which is from the official jQuery Documentation... – Romeo Sierra Commented Apr 26, 2018 at 6:07
- Possible duplicate of JQuery clone <select> element – Romeo Sierra Commented Apr 26, 2018 at 6:08
- If i use clone how can i change id/class to create dinamyc inputs? – Juan Molina Commented Apr 26, 2018 at 6:24
- codereview.stackexchange./questions/69295/… – Death-is-the-real-truth Commented Apr 26, 2018 at 6:27
-
@JuanMolina When you call
$("$elementId").clone()you will get a deep copy of the element which is a jQuery Object. You could use this in a variable probably, to access it's properties.. – Romeo Sierra Commented Apr 26, 2018 at 6:28
5 Answers
Reset to default 4Hi Please check below code:
<html>
<head>
<title>Sample HTML</title>
<script src="https://ajax.googleapis./ajax/libs/jquery/3.3.1/jquery.min.js"></script>
</head>
<body bgcolor=white>
<div id="contenido" class="row text-center">
<div class="col-md-4">
<b>Producto</b>
<select class="form-control" id="producto">
<option value="product1">product1</option>
<option value="product2">product2</option>
<option value="product3">product3</option>
<option value="product4">product4</option>
<option value="product5">product5</option>
<option value="product6">product6</option>
</select><br/>
</div>
<div class="col-md-4">
<b>Cantidad</b>
<input type="number" class="form-control" id="cantidad"><br/>
</div>
<div class="col-md-4">
<b>Precio</b>
<input type="number" class="form-control" id="precio"><br/>
</div>
</div>
<div class="modal-footer">
<button type="button" class="btn agregar_producto" name="crear">Agregar Producto</button>
</div>
<script type="text/javascript">
jQuery(document).ready(function ($) {
$(".agregar_producto").on('click', function() {
var $contenido = $("#contenido:last");
var $clone = $contenido.clone();
$clone.find('input').val('');
$contenido.after($clone);
});
});
</script>
</body>
</html>1.Id need to be unique per element so convert id="contenido" to class="contenido"
2.Use .clone()
$('.agregar_producto').on('click', function(){
var clone = $( ".contenido:first" ).clone();
$(clone).attr('id','changedId'); //change cloned element id attribute
$(clone).find('select').attr('id','changedId1'); //change cloned element children attribute also
$(clone).insertAfter( ".contenido:last" );
});
Note:- add selector(class or id) of the element after which you want to append the clone.
Reference:-
.insertAfter()
Working snippet:-
$('.agregar_producto').on('click', function(){
var clone = $( ".contenido:first" ).clone();
$(clone).attr('id','changedId'); //change cloned element id attribute
$(clone).find('select').attr('id','changedId1'); //change cloned element children attribute also
$(clone).insertAfter( ".contenido:last" );
});#changedId{
background:yellow;
}
#changedId1{
font-size:20px;
color:red;
}<script src="https://ajax.googleapis./ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="modal-body">
<div class="row">
<div class="col-md-5 text-center">
<b>Número Factura</b>
<input type="number" class="form-control" id="numero"><br/>
</div>
<div class="col-md-2 text-center">
-o-
</div>
<div class="col-md-5 text-center">
<b>Número Remisión</b>
<input type="number" class="form-control" id="remision"><br/>
</div>
<div class="col-md-12">
<b>NIT:</b>
<?php $consulta = mysqli_query($conexion, "SELECT * FROM proveedores");
$resultado = mysqli_fetch_all($consulta, MYSQLI_ASSOC); ?>
<select class="form-control" id="proveedor">
<?php foreach($resultado as $r): ?>
<option value="<?php echo $r['nit']; ?>"><?php echo $r['nombre']; ?></option>
<?php endforeach; ?>
</select><br/>
</div>
<div class="col-md-2">
<input type="number" class="form-control" id="productos" value="1">
</div>
<div class="col-md-2">
<button type="button" class="btn btn-success agregar_producto" name="agregar_producto">
<i class="fas fa-user-plus" style="color: black">Click me to append Clone</i>
</button>
</div>
</div>
<br/>
<div class="contenido" class="row text-center">
<div class="col-md-4">
<b>Producto</b>
<select class="form-control" id="producto">
<option value="1">1</option>
<option value="1">2</option>
<option value="1">3</option>
<option value="1">4</option>
<option value="1">5</option>
</select><br/>
</div>
<div class="col-md-4">
<b>Cantidad</b>
<input type="number" class="form-control" id="cantidad"><br/>
</div>
<div class="col-md-4">
<b>Precio</b>
<input type="number" class="form-control" id="precio"><br/>
</div>
</div>
</div>
<div class="modal-footer">
<button type="button" class="btn btn-success crear" name="crear">Agregar Factura</button>
<button type="button" class="btn btn-secondary" data-dismiss="modal">Regresar</button>
</div>.clone() method create a deep copy of the set of matched elements. And .appendTo( ) to append the cloned element.
$('.agregar_producto').on('click', function(){
$( "#contenido" ).clone().appendTo( "body" );
});$('.agregar_producto').click(function(){
$( "#contenido" ).clone().appendTo( "body" );
});
you can change the above to append the clone under specific elements.
You could easily do the following.
<div id="div1">
<p>
Content in DIV1
</p>
</div>
<div id="tgt">
</div>
jQuery snippet would be as follows.
$(document).ready(function(){
var div1 = $("#div1").clone(); //Clone the element. Assigned to the JS variable div1
div1.attr("id", "div1clone"); //Modify the necessary properties using $(element).attr()
$("#tgt").append(div1); //Append the content to where ever desired
});
This is just a very rusty sample. Check this fiddle out to see this in action.