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javascript - jquery .load() with multiple variables - Stack Overflow

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I am using the jquery .load() method for a search. I have figured out how to send one variable, but I need to send many.

WITH ONE

var field1 = ($('#form1 input[name="field1"]:text').val());
$('#results').load("/search/show.php", {field1: field1});

How would I do two variables? THIS WONT WORK

var field1 = ($('#form1 input[name="field1"]:text').val());
var field2 = ($('#form1 input[name="field2"]:text').val());
$('#results').load("/search/show.php", {field1: field1}{field2: field2});

I'm sure there is an easy way to send multiple variables, I just don't know how!

I am using the jquery .load() method for a search. I have figured out how to send one variable, but I need to send many.

WITH ONE

var field1 = ($('#form1 input[name="field1"]:text').val());
$('#results').load("/search/show.php", {field1: field1});

How would I do two variables? THIS WONT WORK

var field1 = ($('#form1 input[name="field1"]:text').val());
var field2 = ($('#form1 input[name="field2"]:text').val());
$('#results').load("/search/show.php", {field1: field1}{field2: field2});

I'm sure there is an easy way to send multiple variables, I just don't know how!

Share edited Dec 20, 2015 at 20:13 Brian Tompsett - 汤莱恩 5,89372 gold badges61 silver badges133 bronze badges asked May 24, 2011 at 2:37 livinzlifelivinzlife 8733 gold badges18 silver badges33 bronze badges
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1 Answer 1

Reset to default 7

You're looking for:

var field1 = ($('#form1 input[name="field1"]:text').val());
var field2 = ($('#form1 input[name="field2"]:text').val());
$('#results').load("/search/show.php", {field1: field1, field2: field2});

Check out object literals on the MDC.

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