I have an array of objects
[
{type:"foo",elements:[...]},
{type:"bar",elements:[...]},
{type:"any",[...]},
{type:"some",elements:[...]}
]
I know how to sort that array by the attribute 'type' using underscore's _.sortBy() method.
But now I need a custom sort order which depends on another array:
["any","foo","some","bar"]
How would my sortBy callback have to look like to sort my objects by my custom order?
I have an array of objects
[
{type:"foo",elements:[...]},
{type:"bar",elements:[...]},
{type:"any",[...]},
{type:"some",elements:[...]}
]
I know how to sort that array by the attribute 'type' using underscore's _.sortBy() method.
But now I need a custom sort order which depends on another array:
["any","foo","some","bar"]
How would my sortBy callback have to look like to sort my objects by my custom order?
Share Improve this question asked Apr 14, 2016 at 10:09 ManuKarachoManuKaracho 1,2182 gold badges15 silver badges32 bronze badges 2- 1 how does your custom order depend on the array ? Is your array an already sorted list of types ? – VonD Commented Apr 14, 2016 at 10:11
- @VonD the reference is a user depended sort order of available types – ManuKaracho Commented Apr 14, 2016 at 10:17
1 Answer
Reset to default 18It's easy:
_.sortBy(yourArrray, function(obj){
return typesArray.indexOf(obj.type);
});
It sorts yourArray
based on position of obj.type
in typesArray
. Types not present in array es first.
Beware - this code have plexity O(kn log n)
. To improve it, use following code:
var yourTypes = {
'any': 1,
'foo': 2,
'some': 3
}
_.sortBy(yourArrray, function(obj){
return yourTypes [obj.type];
});
Object lookups are usually faster, resulting in O(1) access (and overall O(n log n) sorting).