I am able to add the follow button for twitter, subscribe button for youtube and "like" button for facebook, Is is possible to code the follow button for our Instagram account in the website?
JSFiddle: /
<script src=".js"></script>
<div class="g-ytsubscribe" data-channel="GoogleDevelopers" data-layout="default" data-count="default"></div>
<script>window.twttr = (function(d, s, id) {
var js, fjs = d.getElementsByTagName(s)[0],
t = window.twttr || {};
if (d.getElementById(id)) return t;
js = d.createElement(s);
js.id = id;
js.src = ".js";
fjs.parentNode.insertBefore(js, fjs);
t._e = [];
t.ready = function(f) {
t._e.push(f);
};
return t;
}(document, "script", "twitter-wjs"));</script>
<a class="twitter-follow-button" href="" data-show-screen-name="false" data-lang="ar"> Follow @TwitterDev</a>
I am able to add the follow button for twitter, subscribe button for youtube and "like" button for facebook, Is is possible to code the follow button for our Instagram account in the website?
JSFiddle: https://jsfiddle/shmdhussain/jtcz2jtz/2/
<script src="https://apis.google./js/platform.js"></script>
<div class="g-ytsubscribe" data-channel="GoogleDevelopers" data-layout="default" data-count="default"></div>
<script>window.twttr = (function(d, s, id) {
var js, fjs = d.getElementsByTagName(s)[0],
t = window.twttr || {};
if (d.getElementById(id)) return t;
js = d.createElement(s);
js.id = id;
js.src = "https://platform.twitter./widgets.js";
fjs.parentNode.insertBefore(js, fjs);
t._e = [];
t.ready = function(f) {
t._e.push(f);
};
return t;
}(document, "script", "twitter-wjs"));</script>
<a class="twitter-follow-button" href="https://twitter./TwitterDev" data-show-screen-name="false" data-lang="ar"> Follow @TwitterDev</a>
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asked Aug 15, 2016 at 11:37
Mohamed HussainMohamed Hussain
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1 Answer
Reset to default 9Add this fontawesome link tag to your HTML head
<link rel="stylesheet" href="https://use.fontawesome./releases/v5.8.2/css/all.css">
Then put this code where you want to show the Instagram button and change the username to yours
<a href="https://instagram./username">
<span style="font-size: 1.5rem;">
<span style="color: indianred;">
<i class="fab fa-instagram"></i>
</span>
</span>
</a>