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javascript - Show and hide dynamically fields in Django form - Stack Overflow

programmeradmin3浏览0评论

I have a form in Django:

views.py:

class SearchForm(forms.Form):
    type = forms.ChoiceField(choices = ...)
    list1 = forms.ModelMultipleChoiceField(...)
    list2 = forms.ModelMultipleChoiceField(...)

home.htm:

<td valign='top'>{{ form.type }}</td>
<td valign='top'>{{ form.list1 }}</td>
<td valign='top'>{{ form.list2 }}</td>
<td valign='top'><input type="submit" value="Find" /></td>

I want the list1 element to be shown and the list2 to be hide if type is 1 and vice versa in case type is 2. I want them to be hide and shown dynamically without reloading the page or any interaction with the server.

I believe Javascript could be useful here, but I don't know it.

I have a form in Django:

views.py:

class SearchForm(forms.Form):
    type = forms.ChoiceField(choices = ...)
    list1 = forms.ModelMultipleChoiceField(...)
    list2 = forms.ModelMultipleChoiceField(...)

home.htm:

<td valign='top'>{{ form.type }}</td>
<td valign='top'>{{ form.list1 }}</td>
<td valign='top'>{{ form.list2 }}</td>
<td valign='top'><input type="submit" value="Find" /></td>

I want the list1 element to be shown and the list2 to be hide if type is 1 and vice versa in case type is 2. I want them to be hide and shown dynamically without reloading the page or any interaction with the server.

I believe Javascript could be useful here, but I don't know it.

Share Improve this question edited Feb 28, 2013 at 18:14 Nikolay Kovalenko asked Feb 28, 2013 at 13:21 Nikolay KovalenkoNikolay Kovalenko 1,7572 gold badges13 silver badges14 bronze badges 2
  • Do you intend to make this work with or without any further interaction with the server? If you don't want the server to be involved, Javascript is indeed the only way to go. I'd be glad to give an example for both cases, just let us know which method you prefer. – Lukas Bünger Commented Feb 28, 2013 at 17:04
  • Without, using jscript. – Nikolay Kovalenko Commented Feb 28, 2013 at 17:10
Add a ment  | 

2 Answers 2

Reset to default 6

This is an adaption of Andrew's Javascript solution, using Django forms the way you'd usually expect.

The form in Django / Python:

class SearchForm(forms.Form):
    type = forms.ChoiceField(choices = ((1, 'One'), (2, 'Two')))

    # Use any form fields you need, CharField for simplicity reasons
    list1 = forms.CharField()
    list2 = forms.CharField()

The template, assuming an instance of SearchForm got passed to the template context with the name 'form':

<script>
function Hide() {
    if(document.getElementById('id_type').options[document.getElementById('id_type').selectedIndex].value == "1") {
         document.getElementById('id_list1').style.display = 'none';
         document.getElementById('id_list2').style.display = '';
    } else {
         document.getElementById('id_list1').style.display = '';
         document.getElementById('id_list2').style.display = 'none';
    }
}

window.onload = function() {
    document.getElementById('id_type').onchange = Hide;
};
</script>

<div>
    {{ form.type.label_tag }}{{ form.type }}
</div>
<div>
    {{ form.list1.label_tag }}{{ form.list1 }}
</div>
<div>
    {{ form.list2.label_tag }}{{ form.list2 }}
</div>

Try this...

<script>function Hide()
{
    if(document.getElementById('mainselect').options[document.getElementById('mainselect').selectedIndex].value == "1")
    {
         document.getElementById('a').style.display = 'none';
         document.getElementById('b').style.display = '';
    }else
    {
         document.getElementById('a').style.display = '';
         document.getElementById('b').style.display = 'none'
    }
}
</script>
<td valign='top'><select id="mainselect" onchange="Hide()"><option value="1">1</option><option value="2">2</option></select></td>
<td valign='top' id='a'>{{ form.list1 }}</td>
<td valign='top' id='b'>{{ form.list2 }}</td>
<td valign='top'><input type="submit" value="Find" /></td>
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