te')); return $arr; } /* 遍历用户所有主题 * @param $uid 用户ID * @param int $page 页数 * @param int $pagesize 每页记录条数 * @param bool $desc 排序方式 TRUE降序 FALSE升序 * @param string $key 返回的数组用那一列的值作为 key * @param array $col 查询哪些列 */ function thread_tid_find_by_uid($uid, $page = 1, $pagesize = 1000, $desc = TRUE, $key = 'tid', $col = array()) { if (empty($uid)) return array(); $orderby = TRUE == $desc ? -1 : 1; $arr = thread_tid__find($cond = array('uid' => $uid), array('tid' => $orderby), $page, $pagesize, $key, $col); return $arr; } // 遍历栏目下tid 支持数组 $fid = array(1,2,3) function thread_tid_find_by_fid($fid, $page = 1, $pagesize = 1000, $desc = TRUE) { if (empty($fid)) return array(); $orderby = TRUE == $desc ? -1 : 1; $arr = thread_tid__find($cond = array('fid' => $fid), array('tid' => $orderby), $page, $pagesize, 'tid', array('tid', 'verify_date')); return $arr; } function thread_tid_delete($tid) { if (empty($tid)) return FALSE; $r = thread_tid__delete(array('tid' => $tid)); return $r; } function thread_tid_count() { $n = thread_tid__count(); return $n; } // 统计用户主题数 大数量下严谨使用非主键统计 function thread_uid_count($uid) { $n = thread_tid__count(array('uid' => $uid)); return $n; } // 统计栏目主题数 大数量下严谨使用非主键统计 function thread_fid_count($fid) { $n = thread_tid__count(array('fid' => $fid)); return $n; } ?>javascript - pushing new property to objects that are in an array - Stack Overflow
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javascript - pushing new property to objects that are in an array - Stack Overflow

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I got an array person containing many objects that look like this:

const person = [
{ first: 'firstName', last: 'lastName', year: 1439, passed: 1495 },
 ...
]

I have counted how many years the person lived:

const oldest = person.map(x => x.passed - x.year);

Got new array with the years for every person.

Now I would like to push this calculated year as a new property age to each person object in this array.

Can you help me out?

I got an array person containing many objects that look like this:

const person = [
{ first: 'firstName', last: 'lastName', year: 1439, passed: 1495 },
 ...
]

I have counted how many years the person lived:

const oldest = person.map(x => x.passed - x.year);

Got new array with the years for every person.

Now I would like to push this calculated year as a new property age to each person object in this array.

Can you help me out?

Share Improve this question edited Dec 25, 2018 at 14:53 michaelbane asked Dec 25, 2018 at 14:41 michaelbanemichaelbane 1191 silver badge8 bronze badges
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4 Answers 4

Reset to default 11

You could add a new property

person.forEach(p => p.lifetime = p.passed - p.year);

Or map a new array of objects

persons = person.map(p => ({ ...p, lifetime: p.passed - p.year });

You can set the property directly by assigning value To it like this

Person[0].age = oldest[0]:

You can loop like this.

You can use array.forEach, which will iterate through the same array and you can create a new property to the same array.

If you want get a new array you can use array.map, which will create a new array.

I hope this will solve the issue.

const person = [
{ first: 'firstName', last: 'lastName', year: 1439, passed: 1489 },
{ first: 'secondName', last: 'lastName', year: 1499, passed: 1590 },

{ first: 'thirdName', last: 'lastName', year: 1539, passed: 1570 },

{ first: 'fourthName', last: 'lastName', year: 1993, passed: 2018 },

]


person.forEach(obj => obj["age"] = obj.passed - obj.year)


console.log("same array with added age property", person)

Since both arrays person and oldest have the same length, you can just iterate over either, construct new objects with age properties from the elements of both arrays at the same index and push them to a result array.

const person = [
  { first: 'firstName', last: 'lastName', year: 1439, passed: 1495 }
];

const oldest = person.map(x => x.passed - x.year);

const result = [];
person.forEach(({first, last, year, passed}, i) => result.push({first, last, year, passed, age: oldest[i]}));

console.log(result);

Given a zip function (which unfortunately is not yet standard JavaScript), you could also shorten this to:

zip(person, oldest).map(([{first last, year, passed}, age]) => ({first, last, year, passed, age}));
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