Javascript: extract what's after the searched word in a string

I have a string that contains the following :

a test here as well .... Test: 1- (link) 2- (link)

and i want to search for Test and get what it follows after it.

i tried string.includes("Test") but it only returns true or false

I have a string that contains the following :

a test here as well .... Test: 1- (link) 2- (link)

and i want to search for Test and get what it follows after it.

i tried string.includes("Test") but it only returns true or false

Share Improve this question asked Mar 13, 2019 at 13:35 brxnzaz 4911 gold badge5 silver badges15 bronze badges

1 please share the plete string – brk Commented Mar 13, 2019 at 13:36
Just use indexof instead of includes and if > -1 then use that + length of string to substr anything after it. – JBC Commented Mar 13, 2019 at 13:40

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7 Answers 7

Sorted by: Reset to default 7

You could match the wanted word and take all characters after.

var string = 'a test here as well .... Test: 1- (link) 2- (link)',
    part = string.match(/Test(.*$)/)[1];
    
console.log(part);

If the string is likely not to match, you could add a default array for a null value and get undefied instead of a nonmatched part.

var string = 'a test here as well .... Test: 1- (link) 2- (link)',
    part = (string.match(/TestX(.*$)/) || [])[1];
    
console.log(part);

A simple way to do this is to split() the Sting on the text you want and the result[1] will be the text after the splitting string.

so...

var s = 'a test here as well .... Test: 1- (link) 2- (link)';
var splitText = 'Test'
var result = s.split(splitText)[1];

Hope that helps.

First you need to get index of the element that you searched: indexOf
After that you can get extracted text that includes your keyword using slice method.

I have also created a demo that helps you to understand.

const getAfterText = (allText, keyword) => {
  return allText.slice(allText.indexOf(keyword));
};

You may use a capture group inside a regular expression to capture everything after the matched pattern (your string). Below tests if you found it, if you did the value will be stored in the $1 of the RegExp object.

const str = 'a test here as well .... Test: 1- (link) 2- (link)'

if ( /Test(.*)$/.test(str) )
  console.log(RegExp.$1)

Here is another way to functionalize the above:

const text = 'a test here as well .... Test: 1- (link) 2- (link)'
console.log( trailing(text, 'Test') )


  
  
function trailing(str, pattern){
  const re = new RegExp(`${pattern}(.*)$`)
  if ( re.test(str) )
    return RegExp.$1.toString()
  return '' // false and default condition
}

Simpliest way to do it:

const yourString = "a test here as well .... Test: 1- (link) 2- (link)";
const searchTerm = "Test";
const result = yourString.split(searchTerm).at(1);

You can get the index of word and then get the substring.

let str = 'a test here as well .... Test: 1- (link) 2- (link)',
    word = 'Test',
    substring = '';
if(str.indexOf(word) > -1) {
    substring = str.substr(str.indexOf(word) + word.length);
}
console.log(substring);

I believe lastIndexOf and substr is a easy fit for your case:

let text = 'a test here as well .... Test: 1- (link) 2- (link)'
let position = text.lastIndexOf('Test: ')
let result = position > -1 ? text.substr(position + 6) : ''
console.log(result)

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7 Answers 7

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