te')); return $arr; } /* 遍历用户所有主题 * @param $uid 用户ID * @param int $page 页数 * @param int $pagesize 每页记录条数 * @param bool $desc 排序方式 TRUE降序 FALSE升序 * @param string $key 返回的数组用那一列的值作为 key * @param array $col 查询哪些列 */ function thread_tid_find_by_uid($uid, $page = 1, $pagesize = 1000, $desc = TRUE, $key = 'tid', $col = array()) { if (empty($uid)) return array(); $orderby = TRUE == $desc ? -1 : 1; $arr = thread_tid__find($cond = array('uid' => $uid), array('tid' => $orderby), $page, $pagesize, $key, $col); return $arr; } // 遍历栏目下tid 支持数组 $fid = array(1,2,3) function thread_tid_find_by_fid($fid, $page = 1, $pagesize = 1000, $desc = TRUE) { if (empty($fid)) return array(); $orderby = TRUE == $desc ? -1 : 1; $arr = thread_tid__find($cond = array('fid' => $fid), array('tid' => $orderby), $page, $pagesize, 'tid', array('tid', 'verify_date')); return $arr; } function thread_tid_delete($tid) { if (empty($tid)) return FALSE; $r = thread_tid__delete(array('tid' => $tid)); return $r; } function thread_tid_count() { $n = thread_tid__count(); return $n; } // 统计用户主题数 大数量下严谨使用非主键统计 function thread_uid_count($uid) { $n = thread_tid__count(array('uid' => $uid)); return $n; } // 统计栏目主题数 大数量下严谨使用非主键统计 function thread_fid_count($fid) { $n = thread_tid__count(array('fid' => $fid)); return $n; } ?>JavaScript: What is the opposite of the logical operator `A && B`? - Stack Overflow
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JavaScript: What is the opposite of the logical operator `A && B`? - Stack Overflow

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In the following code, what is the opposite of the condition (ran1 <= 63 && ran2 <= 18), which should fit in the else portion of the if statement?

Is it both (ran1 <= 63 || ran2 <= 18) and (! (ran1 <= 63 && ran2 <= 18))?

Logically, I suppose that the opposite of A and B is both A or B and neither A nor B. But I'm not sure how to express the neither A nor B bit in JavaScript.

var ran1 = 1 + Math.floor(Math.random() * 100);
var ran2 = 1 + Math.floor(Math.random() * 100);

if (ran1 <= 63 && ran2 <= 18) {
    // code
} else {
    // code
}

In the following code, what is the opposite of the condition (ran1 <= 63 && ran2 <= 18), which should fit in the else portion of the if statement?

Is it both (ran1 <= 63 || ran2 <= 18) and (! (ran1 <= 63 && ran2 <= 18))?

Logically, I suppose that the opposite of A and B is both A or B and neither A nor B. But I'm not sure how to express the neither A nor B bit in JavaScript.

var ran1 = 1 + Math.floor(Math.random() * 100);
var ran2 = 1 + Math.floor(Math.random() * 100);

if (ran1 <= 63 && ran2 <= 18) {
    // code
} else {
    // code
}
Share Improve this question asked Dec 22, 2015 at 7:36 pourrait Peut-êtrepourrait Peut-être 2911 gold badge3 silver badges9 bronze badges 2
  • 2 ran1 > 63 || ran2 > 18 -- you need to inverse every operand. en.wikipedia/wiki/De_Morgan%27s_laws – zerkms Commented Dec 22, 2015 at 7:38
  • 2 Read on De Morgan's laws. – Amadan Commented Dec 22, 2015 at 7:39
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1 Answer 1

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The mathematical negation of A && B is !A || !B, so in your case, it would be

ran1 > 63 || ran2 > 18 
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