te')); return $arr; } /* 遍历用户所有主题 * @param $uid 用户ID * @param int $page 页数 * @param int $pagesize 每页记录条数 * @param bool $desc 排序方式 TRUE降序 FALSE升序 * @param string $key 返回的数组用那一列的值作为 key * @param array $col 查询哪些列 */ function thread_tid_find_by_uid($uid, $page = 1, $pagesize = 1000, $desc = TRUE, $key = 'tid', $col = array()) { if (empty($uid)) return array(); $orderby = TRUE == $desc ? -1 : 1; $arr = thread_tid__find($cond = array('uid' => $uid), array('tid' => $orderby), $page, $pagesize, $key, $col); return $arr; } // 遍历栏目下tid 支持数组 $fid = array(1,2,3) function thread_tid_find_by_fid($fid, $page = 1, $pagesize = 1000, $desc = TRUE) { if (empty($fid)) return array(); $orderby = TRUE == $desc ? -1 : 1; $arr = thread_tid__find($cond = array('fid' => $fid), array('tid' => $orderby), $page, $pagesize, 'tid', array('tid', 'verify_date')); return $arr; } function thread_tid_delete($tid) { if (empty($tid)) return FALSE; $r = thread_tid__delete(array('tid' => $tid)); return $r; } function thread_tid_count() { $n = thread_tid__count(); return $n; } // 统计用户主题数 大数量下严谨使用非主键统计 function thread_uid_count($uid) { $n = thread_tid__count(array('uid' => $uid)); return $n; } // 统计栏目主题数 大数量下严谨使用非主键统计 function thread_fid_count($fid) { $n = thread_tid__count(array('fid' => $fid)); return $n; } ?>javascript - JQuery click event, not working - Stack Overflow
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javascript - JQuery click event, not working - Stack Overflow

programmeradmin3浏览0评论

I have the following scenario.

I have a index.php page with the following JQuery code included

jQuery(document).ready(function(){
    jQuery('#sIMG img').click(function() {
        var currentSRC = jQuery(this).attr('src');
        var altSRC = jQuery(this).attr('title');
        var imgID = jQuery(this).attr('id');
        var cat = jQuery(this).attr('name');


        /*Fade, Callback, swap the alt and src, fade in */
        jQuery('#main').fadeOut('fast',function() {
            jQuery('#main').load("detail.php?id="+imgID+"&category="+cat);
            jQuery('#main').fadeIn('fast');

         });
    });
});

Now I have two div tags called #main and #right in the index.php page. When I click on a menu item right changes to a bunch of images, if I click on one of those images the above code should take effect and load into the main div, but it's just not working. the images are located within a div called sIMG. Any help will be appreciated

I have the following scenario.

I have a index.php page with the following JQuery code included

jQuery(document).ready(function(){
    jQuery('#sIMG img').click(function() {
        var currentSRC = jQuery(this).attr('src');
        var altSRC = jQuery(this).attr('title');
        var imgID = jQuery(this).attr('id');
        var cat = jQuery(this).attr('name');


        /*Fade, Callback, swap the alt and src, fade in */
        jQuery('#main').fadeOut('fast',function() {
            jQuery('#main').load("detail.php?id="+imgID+"&category="+cat);
            jQuery('#main').fadeIn('fast');

         });
    });
});

Now I have two div tags called #main and #right in the index.php page. When I click on a menu item right changes to a bunch of images, if I click on one of those images the above code should take effect and load into the main div, but it's just not working. the images are located within a div called sIMG. Any help will be appreciated

Share Improve this question edited Apr 4, 2014 at 6:31 Paul 5,2233 gold badges38 silver badges43 bronze badges asked Mar 17, 2010 at 12:44 ElitmiarElitmiar 36.9k77 gold badges182 silver badges233 bronze badges 4
  • Are the images that are loaded in on the right (after clicking a parent image on the right) inserted via javascript or are they just hidden with css when the page loads? – Levi Commented Mar 17, 2010 at 12:47
  • Do you use a JS debugger? Check Firebug for any error messages. – Felix Kling Commented Mar 17, 2010 at 12:48
  • Kindly elaborate on "just not working". Does it run at all? What happens when you stick alert all over the place? – Kobi Commented Mar 17, 2010 at 12:48
  • 1 If the images are dynamically loaded, you'll have to change it to: jQuery('#sIMG img').live('click', function(){ – Jim Schubert Commented Mar 17, 2010 at 12:51
Add a ment  | 

3 Answers 3

Reset to default 12

Try using live

jQuery('#sIMG img').live("click",function(){
});

As of jQuery 1.7, the .live() method is deprecated. Use .on() to attach event handlers.

jQuery('#sIMG img').on("click",function(){
});

I think what you're doing is setting "click" on the array that is return there. Try this:

jQuery('#sIMG img').each(function() {
    jQuery(this).click(function() {

    });
});

One of the reasons that the jquery click don't work is that you have dupplicates id's in the form.

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