te')); return $arr; } /* 遍历用户所有主题 * @param $uid 用户ID * @param int $page 页数 * @param int $pagesize 每页记录条数 * @param bool $desc 排序方式 TRUE降序 FALSE升序 * @param string $key 返回的数组用那一列的值作为 key * @param array $col 查询哪些列 */ function thread_tid_find_by_uid($uid, $page = 1, $pagesize = 1000, $desc = TRUE, $key = 'tid', $col = array()) { if (empty($uid)) return array(); $orderby = TRUE == $desc ? -1 : 1; $arr = thread_tid__find($cond = array('uid' => $uid), array('tid' => $orderby), $page, $pagesize, $key, $col); return $arr; } // 遍历栏目下tid 支持数组 $fid = array(1,2,3) function thread_tid_find_by_fid($fid, $page = 1, $pagesize = 1000, $desc = TRUE) { if (empty($fid)) return array(); $orderby = TRUE == $desc ? -1 : 1; $arr = thread_tid__find($cond = array('fid' => $fid), array('tid' => $orderby), $page, $pagesize, 'tid', array('tid', 'verify_date')); return $arr; } function thread_tid_delete($tid) { if (empty($tid)) return FALSE; $r = thread_tid__delete(array('tid' => $tid)); return $r; } function thread_tid_count() { $n = thread_tid__count(); return $n; } // 统计用户主题数 大数量下严谨使用非主键统计 function thread_uid_count($uid) { $n = thread_tid__count(array('uid' => $uid)); return $n; } // 统计栏目主题数 大数量下严谨使用非主键统计 function thread_fid_count($fid) { $n = thread_tid__count(array('fid' => $fid)); return $n; } ?>Javascript: TypeError variable is undefined - Stack Overflow
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Javascript: TypeError variable is undefined - Stack Overflow

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I am currently building a small web application with similar functionality across all modules. I want to code small generic functions so that all programmers next to me, call these functions and these functions return necessary but important data for them to implement their functionality. In this example, I am trying to deal with the typical "choose true or false" exercise. So from the template.php they call this function:

function checkAnswers(){
var radiobuttons = document.form1.exer1;
var correctAnswers = answers(); //this is an array of string
var checkedAnswers = checkExerciseRB(radiobuttons, 2, correctAnswers);
    for(i=0; i<checkedAnswers.length; i++){
        alert(checkedAnswers[i]);
    }
}

Function checkExerciseRB is my generic function, it is called from checkAnswers.

function checkExerciseRB(rbuttons, opciones, correct){
    var answers = new Array();
    var control = 0;
    for(i=0; i<rbuttons.length; i++){
        var noPick="true";
        for(j=0; j<opciones; j++){
            if(rbuttons[control+j].checked){
                if(rbuttons[control+j].value==correct[i]){
                    answers[i]= 1;
                    noPick="false";
                    break;
                }
                else{
                    answers[i]=2;
                    noPick="false";
                    break;
                }
            }
        }
        if(noPick=="true")
            answers[i]=0;
        control=control+opciones;
    }
    return answers;
}

It works great but while looking at my favorite browsers (FireFox, Chrome) error log it says:

TypeError: rbuttons[control + j] is undefined

Any clue on how to deal with this matter?

I am currently building a small web application with similar functionality across all modules. I want to code small generic functions so that all programmers next to me, call these functions and these functions return necessary but important data for them to implement their functionality. In this example, I am trying to deal with the typical "choose true or false" exercise. So from the template.php they call this function:

function checkAnswers(){
var radiobuttons = document.form1.exer1;
var correctAnswers = answers(); //this is an array of string
var checkedAnswers = checkExerciseRB(radiobuttons, 2, correctAnswers);
    for(i=0; i<checkedAnswers.length; i++){
        alert(checkedAnswers[i]);
    }
}

Function checkExerciseRB is my generic function, it is called from checkAnswers.

function checkExerciseRB(rbuttons, opciones, correct){
    var answers = new Array();
    var control = 0;
    for(i=0; i<rbuttons.length; i++){
        var noPick="true";
        for(j=0; j<opciones; j++){
            if(rbuttons[control+j].checked){
                if(rbuttons[control+j].value==correct[i]){
                    answers[i]= 1;
                    noPick="false";
                    break;
                }
                else{
                    answers[i]=2;
                    noPick="false";
                    break;
                }
            }
        }
        if(noPick=="true")
            answers[i]=0;
        control=control+opciones;
    }
    return answers;
}

It works great but while looking at my favorite browsers (FireFox, Chrome) error log it says:

TypeError: rbuttons[control + j] is undefined

Any clue on how to deal with this matter?

Share Improve this question edited Jul 21, 2012 at 9:23 Teun Zengerink 4,3935 gold badges32 silver badges32 bronze badges asked Jul 20, 2012 at 19:49 mrdeivedmrdeived 851 gold badge2 silver badges7 bronze badges
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3 Answers 3

Reset to default 7

This probably means that control + j is greater than or equal to the length of the array rbuttons. There's no such array element as rbuttons[control + j].

You should learn how to use the JavaScript debugger in your favorite browsers! Debuggers are great. They let you watch this code run, line by line, as fast or as slow as you want, and watch how the value of control changes as you go.

You’ll watch it, and you’ll think “Oh! That line of code is wrong!”

You're looping through rbuttons.length times, but in each loop you're adding 2 to control. Using control to index your array, you're going to run past the end.

Does the index specified by control + j exist in the array? i.e: If that evaluates to 4, is there at least 5 items in the array?

Also, you should be using var i, var j, etc inside your for loop. Without it your variables are leaking into the scope this code is executed in (most likely the global scope, and that's not good) :)

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