te')); return $arr; } /* 遍历用户所有主题 * @param $uid 用户ID * @param int $page 页数 * @param int $pagesize 每页记录条数 * @param bool $desc 排序方式 TRUE降序 FALSE升序 * @param string $key 返回的数组用那一列的值作为 key * @param array $col 查询哪些列 */ function thread_tid_find_by_uid($uid, $page = 1, $pagesize = 1000, $desc = TRUE, $key = 'tid', $col = array()) { if (empty($uid)) return array(); $orderby = TRUE == $desc ? -1 : 1; $arr = thread_tid__find($cond = array('uid' => $uid), array('tid' => $orderby), $page, $pagesize, $key, $col); return $arr; } // 遍历栏目下tid 支持数组 $fid = array(1,2,3) function thread_tid_find_by_fid($fid, $page = 1, $pagesize = 1000, $desc = TRUE) { if (empty($fid)) return array(); $orderby = TRUE == $desc ? -1 : 1; $arr = thread_tid__find($cond = array('fid' => $fid), array('tid' => $orderby), $page, $pagesize, 'tid', array('tid', 'verify_date')); return $arr; } function thread_tid_delete($tid) { if (empty($tid)) return FALSE; $r = thread_tid__delete(array('tid' => $tid)); return $r; } function thread_tid_count() { $n = thread_tid__count(); return $n; } // 统计用户主题数 大数量下严谨使用非主键统计 function thread_uid_count($uid) { $n = thread_tid__count(array('uid' => $uid)); return $n; } // 统计栏目主题数 大数量下严谨使用非主键统计 function thread_fid_count($fid) { $n = thread_tid__count(array('fid' => $fid)); return $n; } ?>Using replace and regex to capitalize first letter of each word of a string in JavaScript - Stack Overflow

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    Using replace and regex to capitalize first letter of each word of a string in JavaScript - Stack Overflow

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    The following,though redundant, works perfectly :

    'leap of, faith'.replace(/([^ \t]+)/g,"$1");

    and prints "leap of, faith", but in the following :

    'leap of, faith'.replace(/([^ \t]+)/g,RegExp.$1); it prints "faith faith faith"

    As a result when I wish to capitalize each word's first character like:

    'leap of, faith'.replace(/([^ \t]+)/g,RegExp.$1.capitalize());

    it doesn't work. Neither does,

    'leap of, faith'.replace(/([^ \t]+)/g,"$1".capitalize);

    because it probably capitalizes "$1" before substituting the group's value.

    I want to do this in a single line using prototype's capitalize() method

    The following,though redundant, works perfectly :

    'leap of, faith'.replace(/([^ \t]+)/g,"$1");

    and prints "leap of, faith", but in the following :

    'leap of, faith'.replace(/([^ \t]+)/g,RegExp.$1); it prints "faith faith faith"

    As a result when I wish to capitalize each word's first character like:

    'leap of, faith'.replace(/([^ \t]+)/g,RegExp.$1.capitalize());

    it doesn't work. Neither does,

    'leap of, faith'.replace(/([^ \t]+)/g,"$1".capitalize);

    because it probably capitalizes "$1" before substituting the group's value.

    I want to do this in a single line using prototype's capitalize() method

    • javascript
    • regex
    • capitalization
    Share Improve this question asked Oct 5, 2011 at 14:29 DaudDaud 7,88718 gold badges78 silver badges124 bronze badges 3
    • Why don't you use .toUpperCase()method ? – Jean-Charles Commented Oct 5, 2011 at 14:32
    • 1 That converts all the characters in a string to upper case, and the OP wants to convert just the first character. – Pointy Commented Oct 5, 2011 at 14:39
    • 2 You could use toUpper + your answer with str.replace(/\b[a-z]/g, function() {return arguments[0].toUpperCase()}) – Alex K. Commented Oct 5, 2011 at 14:44
    Add a ment  | 

    1 Answer 1

    Reset to default 13

    You can pass a function as the second argument of ".replace()":

    "string".replace(/([^ \t]+)/g, function(_, word) { return word.capitalize(); });

    The arguments to the function are, first, the whole match, and then the matched groups. In this case there's just one group ("word"). The return value of the function is used as the replacement.

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