te')); return $arr; } /* 遍历用户所有主题 * @param $uid 用户ID * @param int $page 页数 * @param int $pagesize 每页记录条数 * @param bool $desc 排序方式 TRUE降序 FALSE升序 * @param string $key 返回的数组用那一列的值作为 key * @param array $col 查询哪些列 */ function thread_tid_find_by_uid($uid, $page = 1, $pagesize = 1000, $desc = TRUE, $key = 'tid', $col = array()) { if (empty($uid)) return array(); $orderby = TRUE == $desc ? -1 : 1; $arr = thread_tid__find($cond = array('uid' => $uid), array('tid' => $orderby), $page, $pagesize, $key, $col); return $arr; } // 遍历栏目下tid 支持数组 $fid = array(1,2,3) function thread_tid_find_by_fid($fid, $page = 1, $pagesize = 1000, $desc = TRUE) { if (empty($fid)) return array(); $orderby = TRUE == $desc ? -1 : 1; $arr = thread_tid__find($cond = array('fid' => $fid), array('tid' => $orderby), $page, $pagesize, 'tid', array('tid', 'verify_date')); return $arr; } function thread_tid_delete($tid) { if (empty($tid)) return FALSE; $r = thread_tid__delete(array('tid' => $tid)); return $r; } function thread_tid_count() { $n = thread_tid__count(); return $n; } // 统计用户主题数 大数量下严谨使用非主键统计 function thread_uid_count($uid) { $n = thread_tid__count(array('uid' => $uid)); return $n; } // 统计栏目主题数 大数量下严谨使用非主键统计 function thread_fid_count($fid) { $n = thread_tid__count(array('fid' => $fid)); return $n; } ?>javascript - JSON.stringify and number as string - Stack Overflow
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javascript - JSON.stringify and number as string - Stack Overflow

programmeradmin2浏览0评论

Is there a simple way to deal with this example situation

var data = {
     "phone":  input
}
var payload = JSON.stringify(data);

In the situation where the payload is used in an API call and the API demands that phone value is a string, however, phone numbers can just be entered as numbers or strings e.g. 123777777 or 1237-77777 etc

I tried adding quotes, but JSON.stringify escape them so the end up being part of the final data.

The 'hack' solution I found was to add a trailing space i.e.

var data = {
     "phone":  input + " "
}

But want to know if there is a simple and neat way to deal with this scenario?

Is there a simple way to deal with this example situation

var data = {
     "phone":  input
}
var payload = JSON.stringify(data);

In the situation where the payload is used in an API call and the API demands that phone value is a string, however, phone numbers can just be entered as numbers or strings e.g. 123777777 or 1237-77777 etc

I tried adding quotes, but JSON.stringify escape them so the end up being part of the final data.

The 'hack' solution I found was to add a trailing space i.e.

var data = {
     "phone":  input + " "
}

But want to know if there is a simple and neat way to deal with this scenario?

Share Improve this question asked Mar 6, 2016 at 13:55 Alan FullerAlan Fuller 4916 silver badges13 bronze badges 2
  • So... you don't want the dashes? – Sumner Evans Commented Mar 6, 2016 at 13:59
  • No I want it to be treated as a string, thanks – Alan Fuller Commented Mar 7, 2016 at 22:08
Add a ment  | 

4 Answers 4

Reset to default 9

Strings don't have to have anything in them, so you could do:

var data = {
    "phone": input + ""
};

or "" + input would work as well. But in this situation I usually use the String function:

var data = {
    "phone": String(input)
};

Note: Not new String(...), just String(...).

There's nothing wrong with the input.toString() option others have suggested either, provided you know that input will be something other than null or undefined. (If it were null or undefined, it would cause an error.)

If you want to make sure it's a string call toString() which ensures numbers are parsed as strings.

var data = {
  "phone":  input.toString()
}

Best thing is, that even if you have a string this won't throw an error. It will always be a string. See here for more: https://developer.mozilla/en-US/docs/Web/JavaScript/Reference/Global_Objects/Number/toString

Can always use toString(). This will work even if it is a string

var data = {
     "phone":  input.toString()
}
$( document ).ready(function(){
var input=1234567890;
var data = {
     "phone":  input.toString()
}
console.log("inputType---->"+$.type(input));
var payload = JSON.stringify(data);
console.log("payload----afterstringify--->"+payload);
console.log("dataType------->"+$.type(data.phone));
console.log("payloadType-------->"+$.type(payload));

});
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