te')); return $arr; } /* 遍历用户所有主题 * @param $uid 用户ID * @param int $page 页数 * @param int $pagesize 每页记录条数 * @param bool $desc 排序方式 TRUE降序 FALSE升序 * @param string $key 返回的数组用那一列的值作为 key * @param array $col 查询哪些列 */ function thread_tid_find_by_uid($uid, $page = 1, $pagesize = 1000, $desc = TRUE, $key = 'tid', $col = array()) { if (empty($uid)) return array(); $orderby = TRUE == $desc ? -1 : 1; $arr = thread_tid__find($cond = array('uid' => $uid), array('tid' => $orderby), $page, $pagesize, $key, $col); return $arr; } // 遍历栏目下tid 支持数组 $fid = array(1,2,3) function thread_tid_find_by_fid($fid, $page = 1, $pagesize = 1000, $desc = TRUE) { if (empty($fid)) return array(); $orderby = TRUE == $desc ? -1 : 1; $arr = thread_tid__find($cond = array('fid' => $fid), array('tid' => $orderby), $page, $pagesize, 'tid', array('tid', 'verify_date')); return $arr; } function thread_tid_delete($tid) { if (empty($tid)) return FALSE; $r = thread_tid__delete(array('tid' => $tid)); return $r; } function thread_tid_count() { $n = thread_tid__count(); return $n; } // 统计用户主题数 大数量下严谨使用非主键统计 function thread_uid_count($uid) { $n = thread_tid__count(array('uid' => $uid)); return $n; } // 统计栏目主题数 大数量下严谨使用非主键统计 function thread_fid_count($fid) { $n = thread_tid__count(array('fid' => $fid)); return $n; } ?>Javascript Function with parameters that span multiple lines - Stack Overflow

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    Javascript Function with parameters that span multiple lines - Stack Overflow

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    I want to use a function in javascript that has many parameters that likely have long names. I want it to look something like this:

    functionName( parameter1,
              parameter2,
              parameter3 );

    so far I've tried doing the following to no avail:

    functionName( parameter1, \
              parameter2, \
              parameter3 );

    I understand that "\" is supposed to have things continue on to the next line. Am I missing something?

    I want to use a function in javascript that has many parameters that likely have long names. I want it to look something like this:

    functionName( parameter1,
              parameter2,
              parameter3 );

    so far I've tried doing the following to no avail:

    functionName( parameter1, \
              parameter2, \
              parameter3 );

    I understand that "\" is supposed to have things continue on to the next line. Am I missing something?

    • javascript
    • function
    • parameters
    • multiline
    Share Improve this question asked Jan 15, 2014 at 17:36 user3199313user3199313 631 gold badge1 silver badge5 bronze badges 2
    • Have you tried your code? – elclanrs Commented Jan 15, 2014 at 17:38
    • You obviously mixed up with multiline strings. – VisioN Commented Jan 15, 2014 at 17:39
    Add a ment  | 

    1 Answer 1

    Reset to default 14

    You do not need any special character to span lines. Your original is fine:

    functionName(parameter1,
             parameter2,
             parameter3) {}

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