te')); return $arr; } /* 遍历用户所有主题 * @param $uid 用户ID * @param int $page 页数 * @param int $pagesize 每页记录条数 * @param bool $desc 排序方式 TRUE降序 FALSE升序 * @param string $key 返回的数组用那一列的值作为 key * @param array $col 查询哪些列 */ function thread_tid_find_by_uid($uid, $page = 1, $pagesize = 1000, $desc = TRUE, $key = 'tid', $col = array()) { if (empty($uid)) return array(); $orderby = TRUE == $desc ? -1 : 1; $arr = thread_tid__find($cond = array('uid' => $uid), array('tid' => $orderby), $page, $pagesize, $key, $col); return $arr; } // 遍历栏目下tid 支持数组 $fid = array(1,2,3) function thread_tid_find_by_fid($fid, $page = 1, $pagesize = 1000, $desc = TRUE) { if (empty($fid)) return array(); $orderby = TRUE == $desc ? -1 : 1; $arr = thread_tid__find($cond = array('fid' => $fid), array('tid' => $orderby), $page, $pagesize, 'tid', array('tid', 'verify_date')); return $arr; } function thread_tid_delete($tid) { if (empty($tid)) return FALSE; $r = thread_tid__delete(array('tid' => $tid)); return $r; } function thread_tid_count() { $n = thread_tid__count(); return $n; } // 统计用户主题数 大数量下严谨使用非主键统计 function thread_uid_count($uid) { $n = thread_tid__count(array('uid' => $uid)); return $n; } // 统计栏目主题数 大数量下严谨使用非主键统计 function thread_fid_count($fid) { $n = thread_tid__count(array('fid' => $fid)); return $n; } ?>javascript - .innerHTML <br> breaking - Stack Overflow

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    javascript - .innerHTML <br> breaking - Stack Overflow

    programmeradmin3浏览0评论

    Why is this breaking? I've not used .innerHTML correctly before and don't know why this would be wrong.

    function asdf() {
    document.getElementById("qwerty").innerHTML="A<br>
      B<br>
      C<br>
      D<br>";
}

    Why is this breaking? I've not used .innerHTML correctly before and don't know why this would be wrong.

    function asdf() {
    document.getElementById("qwerty").innerHTML="A<br>
      B<br>
      C<br>
      D<br>";
}
    • javascript
    • innerhtml
    Share Improve this question asked Sep 24, 2013 at 19:32 Kevin BanasKevin Banas 3112 gold badges4 silver badges13 bronze badges 3
    • 1 what do you mean by "breaking"? – iamkrillin Commented Sep 24, 2013 at 19:33
    • 1 Hope the problem is not because of \ !! – Rahul Tripathi Commented Sep 24, 2013 at 19:34
    • 1 stackoverflow./questions/805107/… – u8sand Commented Sep 24, 2013 at 19:34
    Add a ment  | 

    2 Answers 2

    Reset to default 6

    You have to escape new-lines in JavaScript string-literals:

    function asdf() {
    document.getElementById("qwerty").innerHTML="A<br>\
      B<br>\
      C<br>\
      D<br>";
}

    Though you could, potentially more-easily, simply insert newlines in the string itself:

    function asdf() {
    document.getElementById("qwerty").innerHTML = "A<br>\nB<br>\nC<br>\nD<br>";
}

    Javascript string literals cannot contain newlines.

    You can escape the newlines with backslashes: 

    var myString = "a\
b";

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