te')); return $arr; } /* 遍历用户所有主题 * @param $uid 用户ID * @param int $page 页数 * @param int $pagesize 每页记录条数 * @param bool $desc 排序方式 TRUE降序 FALSE升序 * @param string $key 返回的数组用那一列的值作为 key * @param array $col 查询哪些列 */ function thread_tid_find_by_uid($uid, $page = 1, $pagesize = 1000, $desc = TRUE, $key = 'tid', $col = array()) { if (empty($uid)) return array(); $orderby = TRUE == $desc ? -1 : 1; $arr = thread_tid__find($cond = array('uid' => $uid), array('tid' => $orderby), $page, $pagesize, $key, $col); return $arr; } // 遍历栏目下tid 支持数组 $fid = array(1,2,3) function thread_tid_find_by_fid($fid, $page = 1, $pagesize = 1000, $desc = TRUE) { if (empty($fid)) return array(); $orderby = TRUE == $desc ? -1 : 1; $arr = thread_tid__find($cond = array('fid' => $fid), array('tid' => $orderby), $page, $pagesize, 'tid', array('tid', 'verify_date')); return $arr; } function thread_tid_delete($tid) { if (empty($tid)) return FALSE; $r = thread_tid__delete(array('tid' => $tid)); return $r; } function thread_tid_count() { $n = thread_tid__count(); return $n; } // 统计用户主题数 大数量下严谨使用非主键统计 function thread_uid_count($uid) { $n = thread_tid__count(array('uid' => $uid)); return $n; } // 统计栏目主题数 大数量下严谨使用非主键统计 function thread_fid_count($fid) { $n = thread_tid__count(array('fid' => $fid)); return $n; } ?>javascript - regex for single lower case word - Stack Overflow
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javascript - regex for single lower case word - Stack Overflow

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I am looking for a regex pattern that ensures the user puts in a single lower case word with only letters of the alphabet. Basically they are picking a subdomain. Thanks in advance

I am looking for a regex pattern that ensures the user puts in a single lower case word with only letters of the alphabet. Basically they are picking a subdomain. Thanks in advance

Share Improve this question edited Aug 8, 2010 at 11:27 kennytm 523k110 gold badges1.1k silver badges1k bronze badges asked Aug 8, 2010 at 11:20 abarrabarr 1,1404 gold badges13 silver badges28 bronze badges 5
  • Why are you limiting your users to lower-case, presumably ASCII letters for subdomains? That's not all that's allowed in DNS. – Nicholas Knight Commented Aug 8, 2010 at 11:22
  • 1 What language? RegEx dialects have different features, so it's important to know. Java? .NET? Javascript? Perl? Python? Ruby? Something else? – Oded Commented Aug 8, 2010 at 11:22
  • 1 Why not just force the input into lowercase afterwards. It seems unnecessary for an input field to fail validation because you don't allow uppercase characters. Domains are case-insensitive, so however they write the sub-domain doesn't matter. Also, hyphens are allowed in domain names. – Andy E Commented Aug 8, 2010 at 11:23
  • you are right ... forget the lowercase. JS for the programing language and a-z – abarr Commented Aug 8, 2010 at 11:24
  • 7 @Gumbo: Given that he's from Australia I'd guess he means the Australian alphabet, i.e. [z-ɐ]. – Mark Byers Commented Aug 8, 2010 at 11:25
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4 Answers 4

Reset to default 9

The character class [a-z] describes one single character of the alphabet of lowercase letters az. If you want if an input does only contain characters of that class, use this:

^[a-z]+$

^ and $ mark the start and end of the string respectively. And the quantifier + allows one or more repetitions of the preceding expression.

^[a-z]+$ Will find one and only one lower-case word, with no spaces before or after the word.

/^[a-z]+$/

make sure you aren't using 'i' after the last slash

/[a-z]+/

if you are searching for any words within the context

If you want to find all occurrences of lowercase-only ASCII-char words, you can use

text.match(/\b[a-z]+\b/g)

See the regex demo.

Details:

  • \b - a word boundary
  • [a-z]+ - one or more (+) lowercase ASCII letters
  • \b - a word boundary

The g flag makes it extract all occurrences.

See the JavaScript demo:

const text = "123456789 Ticket number (CO2) text";
console.log(text.match(/\b[a-z]+\b/g));

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