te')); return $arr; } /* 遍历用户所有主题 * @param $uid 用户ID * @param int $page 页数 * @param int $pagesize 每页记录条数 * @param bool $desc 排序方式 TRUE降序 FALSE升序 * @param string $key 返回的数组用那一列的值作为 key * @param array $col 查询哪些列 */ function thread_tid_find_by_uid($uid, $page = 1, $pagesize = 1000, $desc = TRUE, $key = 'tid', $col = array()) { if (empty($uid)) return array(); $orderby = TRUE == $desc ? -1 : 1; $arr = thread_tid__find($cond = array('uid' => $uid), array('tid' => $orderby), $page, $pagesize, $key, $col); return $arr; } // 遍历栏目下tid 支持数组 $fid = array(1,2,3) function thread_tid_find_by_fid($fid, $page = 1, $pagesize = 1000, $desc = TRUE) { if (empty($fid)) return array(); $orderby = TRUE == $desc ? -1 : 1; $arr = thread_tid__find($cond = array('fid' => $fid), array('tid' => $orderby), $page, $pagesize, 'tid', array('tid', 'verify_date')); return $arr; } function thread_tid_delete($tid) { if (empty($tid)) return FALSE; $r = thread_tid__delete(array('tid' => $tid)); return $r; } function thread_tid_count() { $n = thread_tid__count(); return $n; } // 统计用户主题数 大数量下严谨使用非主键统计 function thread_uid_count($uid) { $n = thread_tid__count(array('uid' => $uid)); return $n; } // 统计栏目主题数 大数量下严谨使用非主键统计 function thread_fid_count($fid) { $n = thread_tid__count(array('fid' => $fid)); return $n; } ?>javascript - Why is replace('<br>g', 'n') not working - Stack Overflow

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    javascript - Why is replace('<br>g', 'n') not working - Stack Overflow

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    "test<br>test<br>test<br>test".replace('/<br>/g', '\n');

    Does not replace the <br>'s with \n, it leaves the string unchanged. I can't figure out why. 

    "test<br>test<br>test<br>test".replace('/<br>/g', '\n');

    Does not replace the <br>'s with \n, it leaves the string unchanged. I can't figure out why.

    • javascript
    Share Improve this question asked Apr 7, 2014 at 17:49 BoydBoyd 7634 gold badges17 silver badges32 bronze badges 2
    • 6 '/<br>/g' is a string, not a regex. Lose the quotes. It's looking for the literal string '/<br>/g'. You want .replace(/<br>/g, '\n');. JavaScript has RegEx literals. – gen_Eric Commented Apr 7, 2014 at 17:51
    • 1 duplicate of stackoverflow./questions/8062399/… – Mostafa Berg Commented Apr 7, 2014 at 17:52
    Add a ment  | 

    2 Answers 2

    Reset to default 15

    Because you're passing the regex object as a string instead of a regex. Remove the '' from the first argument you're passing to replace()

    You need to use a Regex literal, not a string:

    "test<br>test<br>test<br>test".replace(/<br>/g, '\n');

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