te')); return $arr; } /* 遍历用户所有主题 * @param $uid 用户ID * @param int $page 页数 * @param int $pagesize 每页记录条数 * @param bool $desc 排序方式 TRUE降序 FALSE升序 * @param string $key 返回的数组用那一列的值作为 key * @param array $col 查询哪些列 */ function thread_tid_find_by_uid($uid, $page = 1, $pagesize = 1000, $desc = TRUE, $key = 'tid', $col = array()) { if (empty($uid)) return array(); $orderby = TRUE == $desc ? -1 : 1; $arr = thread_tid__find($cond = array('uid' => $uid), array('tid' => $orderby), $page, $pagesize, $key, $col); return $arr; } // 遍历栏目下tid 支持数组 $fid = array(1,2,3) function thread_tid_find_by_fid($fid, $page = 1, $pagesize = 1000, $desc = TRUE) { if (empty($fid)) return array(); $orderby = TRUE == $desc ? -1 : 1; $arr = thread_tid__find($cond = array('fid' => $fid), array('tid' => $orderby), $page, $pagesize, 'tid', array('tid', 'verify_date')); return $arr; } function thread_tid_delete($tid) { if (empty($tid)) return FALSE; $r = thread_tid__delete(array('tid' => $tid)); return $r; } function thread_tid_count() { $n = thread_tid__count(); return $n; } // 统计用户主题数 大数量下严谨使用非主键统计 function thread_uid_count($uid) { $n = thread_tid__count(array('uid' => $uid)); return $n; } // 统计栏目主题数 大数量下严谨使用非主键统计 function thread_fid_count($fid) { $n = thread_tid__count(array('fid' => $fid)); return $n; } ?>javascript - How to add a variable to URL of $.ajax({ url : " "}); - Stack Overflow

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    javascript - How to add a variable to URL of $.ajax({ url : " "}); - Stack Overflow

    programmeradmin4浏览0评论

    I want the user to be able to change a part of the URL address to their post code. I have a text box and button which I am hoping will submit the value to the URL.

    jQuery:

    jQuery(document).ready(function($) {
    $.ajax({ 
        url : "/" + PostCode + ".json",
        dataType : "jsonp",
        success : function(parsed_json) {

    HTML:

    <input type="text" id="GetPostCode" />
<button id="SetPostCode">Set This Post Code</button>

    jQuery:

    $("#SetPostCode").click(function() {
    var PostCode = document.getElementById("GetPostCode").value;
    $("#GetPostCode").val(" ");
    return false;
});

    I understand that the line

    $.ajax({ 
    url : "/" + PostCode + ".json",

    does not work that way, but I didn't know what else to do. Could someone please show me what I need to do in order for this to work?

    I want the user to be able to change a part of the URL address to their post code. I have a text box and button which I am hoping will submit the value to the URL.

    jQuery:

    jQuery(document).ready(function($) {
    $.ajax({ 
        url : "http://SomeAddress./" + PostCode + ".json",
        dataType : "jsonp",
        success : function(parsed_json) {

    HTML:

    <input type="text" id="GetPostCode" />
<button id="SetPostCode">Set This Post Code</button>

    jQuery:

    $("#SetPostCode").click(function() {
    var PostCode = document.getElementById("GetPostCode").value;
    $("#GetPostCode").val(" ");
    return false;
});

    I understand that the line

    $.ajax({ 
    url : "http://api.wunderground./api/2508132ae0c7601a/geolookup/conditions/q/UK/" + PostCode + ".json",

    does not work that way, but I didn't know what else to do. Could someone please show me what I need to do in order for this to work?

    • javascript
    • jquery
    • ajax
    • url
    • input
    Share Improve this question edited Dec 27, 2012 at 3:21 BalusC 1.1m376 gold badges3.6k silver badges3.6k bronze badges asked Dec 27, 2012 at 3:14 ChristopherStrydomChristopherStrydom 8,1765 gold badges24 silver badges35 bronze badges 4
    • 2 The only reason that wouldn't work were if PostCode wasn't global.. If it was your sorted – cjds Commented Dec 27, 2012 at 3:19
    • 2 Why don't you do the $.ajax after the line var PostCode inside the click handler? – BalusC Commented Dec 27, 2012 at 3:20
    • 1 +1 @CarlSaldanha You set your PostCode variable in the click function therefore, you can't access it from other places. – wakooka Commented Dec 27, 2012 at 3:21
    • Well that was simple... Thanks Guys – ChristopherStrydom Commented Dec 27, 2012 at 3:43
    Add a ment  | 

    1 Answer 1

    Reset to default 9 
    jQuery(document).ready(function($) {

   var PostCode=1;
   $.ajax({ url : "http://SomeAddress./"+PostCode +".json",
   dataType : "jsonp"
   //.... more stuff
  });


  $("#SetPostCode").click(function() {
     PostCode = document.getElementById("GetPostCode").value;
     $("#GetPostCode").val(" ");
     return false; 
  });

});

    Above would work as PostCode is now global to the jQuery and can be accessed anywhere

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