te')); return $arr; } /* 遍历用户所有主题 * @param $uid 用户ID * @param int $page 页数 * @param int $pagesize 每页记录条数 * @param bool $desc 排序方式 TRUE降序 FALSE升序 * @param string $key 返回的数组用那一列的值作为 key * @param array $col 查询哪些列 */ function thread_tid_find_by_uid($uid, $page = 1, $pagesize = 1000, $desc = TRUE, $key = 'tid', $col = array()) { if (empty($uid)) return array(); $orderby = TRUE == $desc ? -1 : 1; $arr = thread_tid__find($cond = array('uid' => $uid), array('tid' => $orderby), $page, $pagesize, $key, $col); return $arr; } // 遍历栏目下tid 支持数组 $fid = array(1,2,3) function thread_tid_find_by_fid($fid, $page = 1, $pagesize = 1000, $desc = TRUE) { if (empty($fid)) return array(); $orderby = TRUE == $desc ? -1 : 1; $arr = thread_tid__find($cond = array('fid' => $fid), array('tid' => $orderby), $page, $pagesize, 'tid', array('tid', 'verify_date')); return $arr; } function thread_tid_delete($tid) { if (empty($tid)) return FALSE; $r = thread_tid__delete(array('tid' => $tid)); return $r; } function thread_tid_count() { $n = thread_tid__count(); return $n; } // 统计用户主题数 大数量下严谨使用非主键统计 function thread_uid_count($uid) { $n = thread_tid__count(array('uid' => $uid)); return $n; } // 统计栏目主题数 大数量下严谨使用非主键统计 function thread_fid_count($fid) { $n = thread_tid__count(array('fid' => $fid)); return $n; } ?>javascript - How to use pixi.js without Stage? - Stack Overflow
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javascript - How to use pixi.js without Stage? - Stack Overflow

programmeradmin2浏览0评论

I have this pixi.js code which does what it's supposed to do: Draw a rectangle.

   var stage, renderer, graphics;

    (function () {
      // init PIXI
      // create an new instance of a pixi stage
      stage = new PIXI.Stage(0x66FF99);

      // create a renderer instance.
      renderer = PIXI.autoDetectRenderer(400, 300);

      $('#pixi-area').append(renderer.view);

      graphics = new PIXI.Graphics();
      graphics.beginFill(0xFFFFFF);
      graphics.lineStyle(1, 0xFF0000);
      graphics.drawRect(20, 20, 150, 150);
      stage.addChild(graphics);
      renderer.render(stage);
    }());

However, in the console I get the statement

You do not need to use a PIXI Stage any more, you can simply render any container.

How am I supposed to do the same without using PIXI.Stage()?

I have this pixi.js code which does what it's supposed to do: Draw a rectangle.

   var stage, renderer, graphics;

    (function () {
      // init PIXI
      // create an new instance of a pixi stage
      stage = new PIXI.Stage(0x66FF99);

      // create a renderer instance.
      renderer = PIXI.autoDetectRenderer(400, 300);

      $('#pixi-area').append(renderer.view);

      graphics = new PIXI.Graphics();
      graphics.beginFill(0xFFFFFF);
      graphics.lineStyle(1, 0xFF0000);
      graphics.drawRect(20, 20, 150, 150);
      stage.addChild(graphics);
      renderer.render(stage);
    }());

However, in the console I get the statement

You do not need to use a PIXI Stage any more, you can simply render any container.

How am I supposed to do the same without using PIXI.Stage()?

Share Improve this question asked May 14, 2015 at 12:27 BetaRideBetaRide 16.8k31 gold badges107 silver badges189 bronze badges 1
  • Hi @BetaRide, did my suggestion work for you? Do you have any questions that you would like to ask? Feel free. – Tahir Ahmed Commented Jun 23, 2015 at 6:24
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3 Answers 3

Reset to default 9

I actually just ran into the same problem! I ended up finding the newer documentation for PIXI, which can be found here http://pixijs.github.io/docs/index.html.

The container that they are referring to is a new object introduced to replace the Stage object. http://pixijs.github.io/docs/PIXI.Container.html#toc1

stage = new PIXI.Stage(0x66FF99)

now bees,

var container = new PIXI.Container();

Hope this helps! :)

You should move from:

var stage = new PIXI.Stage(0x65C25D);

To:

var stage = new PIXI.Container();

And if you want to still use background color you can specify it when declaring renderer:

var renderer = PIXI.autoDetectRenderer(width, height, {
    backgroundColor: 0x65C25D
});

As @Mattnv92 mentioned, any object that inherits from Container (formarly DisplayObjectContainer) e.g. Sprite, Graphics etc can now be directly rendered to canvas, if I am not mistaken.

So changing stage = new PIXI.Stage(0x66FF99); to stage = new PIXI.Container(); should do.

T

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