So I try to find the minimum and maximum if an array and want to call the function. I made this code, but it doesn´t work. I just don´t get why.

function getMinMax(arr){
  let maximum = Math.max(arr);
  let minimum = Math.min(arr);
 let result =  ([maximum, minimum]); 
  return result;
};

getMinMax([10,3,8,1,33])

So I try to find the minimum and maximum if an array and want to call the function. I made this code, but it doesn´t work. I just don´t get why.

function getMinMax(arr){
  let maximum = Math.max(arr);
  let minimum = Math.min(arr);
 let result =  ([maximum, minimum]); 
  return result;
};

getMinMax([10,3,8,1,33])

• javascript
• arrays

• 3 just have a look here: spread syntax ... – Nina Scholz Commented Jul 15, 2020 at 8:51
• The reason why you code doesn't work is because both Math.min and Math.max expect separate arguments, not a single array argument. eg Math.max(10,3,8,1,33) is valid Math.max([10,3,8,1,33]) isn't. – 3limin4t0r Commented Jul 15, 2020 at 8:59
• 1 Does this answer your question? Find the min/max element of an Array in JavaScript – Sergey Shubin Commented Jul 15, 2020 at 9:02

6 Answers 6

You try to pass array, but functions (min, max) accept only number arguments.

You need to unpack array to array of arguments with the spread operator (...):

const arr = [10, 3, 8, 1, 33];
const min = Math.min(...arr);
const max = Math.max(...arr);

So, your code should be like this:

function getMinMax(arr){
  let maximum = Math.max(...arr);
  let minimum = Math.min(...arr);
 let result =  ([maximum, minimum]); 
  return result;
};

getMinMax([10,3,8,1,33])

You can find the maximum and minimum in 2 ways. First way You go on with maximum and minimum form Math function in javascript, if you need to be used when you have to set numbers from max and min, like this :

let maximum = Math.max(10, 3, 8, 1, 33);
let minimum = Math.min(10, 3, 8, 1, 33);

Now you have an array so you have to convert to As above, for example : let array = [1,2,3,4,5] when you use ... before array you convert array to this : 1,2,3,4,5 for example :

function getMinMaxWithMath(arr){
  // Math.max(10,3,8,1,33)
  let maximum = Math.max(...arr);
  // Math.min(10,3,8,1,33)
  let minimum = Math.min(...arr);
 let result =  ([maximum, minimum]); 
  return result;
};

console.log('getMinMaxWithMath ', getMinMaxWithMath([10,3,8,1,33]));

The second way you can use for loop for example :

function getMinMaxForLoop(arr){
  let maximum = arr[0];
  let minimum = arr[0];
  for (let i = 0 ; i < arr.length; i++) {
    if (maximum < arr[i]) {
      maximum = arr[i];
    } else {
      minimum = arr[i];
    }
    
  }
 let result =  ([maximum, minimum]); 
  return result;
};
console.log('getMinMaxForLoop : ',getMinMaxForLoop([10,3,8,1,33]))

You can Look output from this link;

It's just ...

  Math.max(...arrayName)

If you want to use this method, you need to structure the array

function getMinMax(arr) {
    let maximum = Math.max(...arr);
    let minimum = Math.min(...arr);
    let result = [maximum, minimum];
    return result;
};

getMinMax([10, 3, 8, 1, 33]);

const getMinMax = (arr) => {
  const sortedArr = arr.sort((a,b) => a - b);
  const min = sortedArr[0];
  const max = sortedArr[sortedArr.length - 1];
  return [min, max];
};

console.log(getMinMax([10,3,8,1,33]))

You also can use Array.sort() to achieve your desired result.

Or, as a one-liner (nothing new, only more pact):

const getMinMax=arr=>[Math.min(...arr),Math.max(...arr)];

console.log(getMinMax([10,3,8,1,33]))

You can also try this simple and understandable math

Example

function max(arr) {
  let i;
  let max = arr[0]
  let min = arr[0]
  for (let i = 0; i < arr.length; i++) {
    if (arr[i] > max) {
      max = arr[i]
    } else if (arr[i] < min) {
      min = arr[i]
    }
  }
  let res = (["min: " + min, "max: " + max])
  return res
}

console.log(max([10, 3, 8, 1, 33]))