I have this
$ cat test.sh
echo ".git"
echo "ssh://[email protected]:6699/xyz/abc.git"
echo ";
echo "ssh://[email protected]/xyz/abc"
echo ";
echo "ssh://[email protected]/xyz/abc.git"
I want an one liner command (preferably sed command) that will extract the server name from the URL. e.g.
bitbucket.dev.global.server
I tried this but it doesn't work
$ ./test.sh | sed 's/\(\/\/\|\@\)/&\n/;s/.*\n//;s/\(\:\|\/\)/\n&/;s/\n.*//'
bitbucket.dev.global.server
[email protected]
bitbucket.dev.global.server
[email protected]
bitbucket.dev.global.server
[email protected]
It still got the user and @ symbol. How to do this?
I have this
$ cat test.sh
echo "https://bitbucket.dev.global.server/scm/xyz/abd.git"
echo "ssh://[email protected]:6699/xyz/abc.git"
echo "http://bitbucket.dev.global.server/abc"
echo "ssh://[email protected]/xyz/abc"
echo "http://bitbucket.dev.global.server"
echo "ssh://[email protected]/xyz/abc.git"
I want an one liner command (preferably sed command) that will extract the server name from the URL. e.g.
bitbucket.dev.global.server
I tried this but it doesn't work
$ ./test.sh | sed 's/\(\/\/\|\@\)/&\n/;s/.*\n//;s/\(\:\|\/\)/\n&/;s/\n.*//'
bitbucket.dev.global.server
[email protected]
bitbucket.dev.global.server
[email protected]
bitbucket.dev.global.server
[email protected]
It still got the user and @ symbol. How to do this?
Share Improve this question edited 14 hours ago Ramanan T asked 14 hours ago Ramanan TRamanan T 3733 silver badges13 bronze badges 1- Please edit your question to show all the expected output, not just 1 line of it. – Ed Morton Commented 7 mins ago
3 Answers
Reset to default 2I want an one liner command (preferably sed command)
Since you requested a sed one-liner, you can try this:
./test.sh | sed -E 's|.*://([^/@:]+@)?([^/@:]+).*|\2|'
which outputs this:
bitbucket.dev.global.server
bitbucket.dev.global.server
bitbucket.dev.global.server
bitbucket.dev.global.server
bitbucket.dev.global.server
bitbucket.dev.global.server
Explanation:
./test.sh | sed -E '
s| .*:// # Match all up to "://"
([^/@:]+@)? # Match "user@" or "git@"
([^/@:]+) # The hostname
.* # Match all after the hostname and discard it
|\2|' # Replace full match with hostname, and then it's done
Try this, using perl, sed like syntax:
bash test.sh | perl -pe 's|.*://(?:\w+@)?([\w.]+)/?.*|\1|'
The regular expression matches as follows:
| Node | Explanation |
|---|---|
.* |
any character except \n (0 or more times (matching the most amount possible)) |
:// |
'://' |
(?: |
group, but do not capture (optional (matching the most amount possible)): |
\w+ |
word characters (a-z, A-Z, 0-9, _) (1 or more times (matching the most amount possible)) |
@ |
@ |
)? |
end of grouping |
( |
group and capture to \1: |
[\w.]+ |
any character of: word characters (a-z, A-Z, 0-9, _), '.' (1 or more times (matching the most amount possible)) |
) |
end of \1 |
/? |
'/' (optional (matching the most amount possible)) |
.* |
any character except \n (0 or more times (matching the most amount possible)) |
or with GNU grep in PCRE mode:
bash test.sh | grep -oP '://(?:\w+@)?\K[\w.]+(?>=/)?'
The regular expression matches as follows:
| Node | Explanation |
|---|---|
:// |
'://' |
(?: |
group, but do not capture (optional (matching the most amount possible)): |
\w+ |
word characters (a-z, A-Z, 0-9, _) (1 or more times (matching the most amount possible)) |
@ |
@ |
)? |
end of grouping |
\K |
resets the start of the match (what is Kept) as a shorter alternative to using a look-behind assertion: look arounds and Support of \K in regex |
[\w.]+ |
any character of: word characters (a-z, A- Z, 0-9, _), '.' (1 or more times (matching the most amount possible)) |
(?> |
match (and do not backtrack afterwards) (optional (matching the most amount possible)): |
=/ |
'=/' |
)? |
end of look-ahead |
yields:
bitbucket.dev.global.server
bitbucket.dev.global.server
bitbucket.dev.global.server
bitbucket.dev.global.server
bitbucket.dev.global.server
bitbucket.dev.global.server
You can do this:
echo "https://bitbucket.dev.global.server/scm/xyz/abd.git" | sed 's/$/\//' | grep -Eo /[^/]*/[^/]*/ | head -1 | sed 's|[/]||g'
Explanation:
- we echo the string
- we add a
/at the end to have consistent format - we
grepout the pattern of/- anything different from
/ /- anything different from
/ /
- we get the first match
- we remove the
/characters