I have a string with the following format: '01/02/2016' and I am trying to get rid of the leading zeros so that at the end I get '1/2/2016' with regex.

Tried '01/02/2016'.replace(/^0|[^\/]0./, ''); so far, but it only gives me 1/02/2016

Any help is appreciated.

I have a string with the following format: '01/02/2016' and I am trying to get rid of the leading zeros so that at the end I get '1/2/2016' with regex.

Tried '01/02/2016'.replace(/^0|[^\/]0./, ''); so far, but it only gives me 1/02/2016

Any help is appreciated.

• javascript
• regex
• date

• 1 not plete duplicate and don't flag Remove leading zeroes in datestring – Mahi Commented Dec 20, 2016 at 15:50
• 1 Apart from missing g flag, the ^ doesn't mean "start of" when used inside []. – Álvaro González Commented Dec 20, 2016 at 15:54
• You could replace [^\/] with \/, but mbomb007's answer is better as it supports any separator, not just "/". ;-) – RobG Commented Dec 20, 2016 at 20:33

2 Answers 2

Replace \b0 with empty string. \b represents the border between a word character and a non-word character. In your case, \b0 will match a leading zero.

var d = '01/02/2016'.replace(/\b0/g, '');
console.log(d); // 1/2/2016

var d = '10/30/2020'.replace(/\b0/g, '');
console.log(d); // 10/30/2020 (stays the same)

You can use String.prototype.replace() and regular expression to replace the zero at the binning and the zero before / like this:

var d = '01/02/2016'.replace(/(^|\/)0+/g, '$1');
console.log(d);