I want to wrap all occurrences of certain words in a given string with square brackets in JavaScript.
Say these words are apples, oranges, and bananas. Then a subject text "You are paring apples to oranges."
should turn into "You are paring [apples] to [oranges]."
The regular expression for this would be (apples|oranges)
, but the question is how to wrap or more generally, modify each match. String.replace()
lets you replace matches founds with some pre-defined value, rather a value based on the match.
Thanks.
I want to wrap all occurrences of certain words in a given string with square brackets in JavaScript.
Say these words are apples, oranges, and bananas. Then a subject text "You are paring apples to oranges."
should turn into "You are paring [apples] to [oranges]."
The regular expression for this would be (apples|oranges)
, but the question is how to wrap or more generally, modify each match. String.replace()
lets you replace matches founds with some pre-defined value, rather a value based on the match.
Thanks.
Share Improve this question edited Jan 26, 2011 at 20:21 Tom Tucker asked Jan 26, 2011 at 19:54 Tom TuckerTom Tucker 11.9k23 gold badges93 silver badges130 bronze badges 1-
2
Actually, the regexp for that would be
(apples|oranges)
... – gnarf Commented Jan 26, 2011 at 20:04
4 Answers
Reset to default 7js> var str = 'You are paring apples to oranges.';
js> str.replace(/(apples|oranges)/g, '[$1]')
You are paring [apples] to [oranges].
If you prefer a function where you can simply feed an array of words:
function reg_quote(str, delimiter) {
return (str+'').replace(new RegExp('[.\\\\+*?\\[\\^\\]$(){}=!<>|:\\'+(delimiter || '')+'-]', 'g'), '\\$&');
}
function mark_words(str, words) {
for(var i = 0; i < words.length; i++) {
words[i] = reg_quote(words[i]);
}
return str.replace(new RegExp('(' + words.join('|') + ')', 'g'), '[$1]')
}
Demo:
js> mark_words(str, ['apples', 'oranges']);
You are paring [apples] to [oranges].
js> mark_words(str, ['apples', 'You', 'oranges']);
[You] are paring [apples] to [oranges].
If you want it case insensitive, replace 'g'
with 'gi'
.
In addition to the simple substitution string mentioned by others, you can also pass a function to String.replace()
which is called for each match, and whose return value is substituted into the resulting string. This lets you do more plicated transformations. For details, see:
https://developer.mozilla/en/JavaScript/Reference/Global_Objects/String/replace#Specifying_a_function_as_a_parameter
'You are paring apples to oranges.'.replace(/(apples|oranges)/g, "[$1]");
//"You are paring [apples] to [oranges]."
This is a very ugly code, but it does the job:
var string = "You are paring apples to oranges";
var regEx = "(apples|oranges)";
var re = new RegExp(regEx, "g");
for (var i=0; i<string.match(re).length; i++)
{
string = string.replace(string.match(re)[i], "[" + string.match(re)[i] + "]");
}
alert(string);