I am stuck with a strange issue with React.
this.state={
testState: { testValue: "Test State" }
}
testFn = () => {
let a;
a = this.state.testState
a.testValue = "Debugging is awesome";
console.log(this.state.testState)
}
I am stuck with a strange issue with React.
this.state={
testState: { testValue: "Test State" }
}
testFn = () => {
let a;
a = this.state.testState
a.testValue = "Debugging is awesome";
console.log(this.state.testState)
}
If I have made any change in the assigned variable a
, then it will reflect in the state also.
What I got in console is,
{testValue: "Debugging is awesome"}
.
Any help will be appreciable
Edit:
I don't want to change the state. I have to modify a
without altering the state. How can I achieve this?
-
testState
is an object and you're modifying it. What are you looking to achieve? – maazadeeb Commented Mar 9, 2020 at 8:40
7 Answers
Reset to default 10The state changes because your variable a
holds a reference to testState
. This is a no-op. You should never change it directly and only use the setState
function provided by react.
this.setState({ testState: { testValue: "Debugging is awesome" } });
If you don't want to change the state you can use the spread operator:
let a = { ...this.state.testState };
Why does it act this way?
It's because objects
and arrays
in JavaScript are reference values. Wherever you update its value, it also updates the source. In this case, you'd want to make it immutable. You would do that by assigning a new object. In ES6 this can be done with the spread operator
.
Solution
let a = { ...this.state.testState };
Further reading
- Mozilla Web Docs: Spread syntax
You have to deep copy the state if you don't want it to be effected (Object.assign):
this.state={
testState: { testValue: "Test State" }
}
testFn = () => {
let a;
a = Object.assign({}, this.state.testState);
a.testValue = "Debugging is awesome";
console.log(this.state.testState)
}
Or you can use {...this.state.testState}
instead of Object.assign
Note that using the spread operator {...}
will not keep the prototype property (instanceof
).
You can use the spread operator to create a copy of an object
const newObj = {...obj};
Using JS, when you affect an object to a variable (here, testState
), it is passed by reference (See here for further explanation).
This means that if you modify the object through one of the variables, every variable referencing the source will have the change applied.
To solve your problem, you can use the spread operator, which copies the object without referencing it directly:
let a = {...this.state.testState}
try:
this.state={
testState: { testValue: "Test State" }
}
testFn = () => {
const a = { ...this.state.testState };
a.testValue = "Debugging is awesome";
console.log(this.state.testState)
}
You have to use spread operator (...) for this instead of assigning directly.
this.state={
testState: { testValue: "Test State" }
}
testFn = () => {
let a;
a = {...this.state.testState}
a.testValue = "Debugging is awesome";
console.log(this.state.testState)
}
testFn()