If I have a
var t = document.createTextNode(text)
parent.appendChild(t);
Is it possible to simply update the contents of t
?
I would like to change the text inside the parent
without using removeChild
, createTextNode
and appendChild
. Why would I need this instead of just using innerHTML
? Because I don't want to update the contents of the element with HTML code and the text
may contain special characters, such as < or & which should be parsed by TextNode
's DOM methods.
Thanks,
Tom
If I have a
var t = document.createTextNode(text)
parent.appendChild(t);
Is it possible to simply update the contents of t
?
I would like to change the text inside the parent
without using removeChild
, createTextNode
and appendChild
. Why would I need this instead of just using innerHTML
? Because I don't want to update the contents of the element with HTML code and the text
may contain special characters, such as < or & which should be parsed by TextNode
's DOM methods.
Thanks,
Tom
- Do you want to display actual HTML or really just plain text? – Tomalak Commented May 5, 2009 at 9:15
- I want to change the text inside parent and make it appear as plain text (ie, have the DOM replace < with <). – Tom Commented May 5, 2009 at 9:26
4 Answers
Reset to default 11Be aware that adjacent text nodes are collapsed into one (since there is really no way to distinguish two adjacent text nodes).
The contents of a text node can be updated using it's nodeValue
property (see MDC).
Since a text node by it's very definition cannot contain any markup, there is no innerHTML
property.
If you keep the instance of the TextNode object (t in your example code) then you can change the content using various functions like replaceData(), substringData(), etc..
See this page for a nice reference: http://msdn.microsoft.com/en-us/library/ms535905(VS.85).aspx#
parent.innerText = text;
Below example code overwrites the "Old Value" of the text node with the "New Value".
const textNode = document.createTextNode("Old Value");
parent.appendChild(textNode);
textNode.nodeValue = "New Value";