There's the standard npm semver version comparison library, but I have some simple logic to compare semver versions here:
const versionA = '14.8.3';
const versionB = '15.1.1';
const versionC = '15.1.2';
const semver = require('semver');
const assert = require('assert');
const isGreater = (a, b) => {
const [majorA, minorA, patchA] = String(a).split('.').map(v => Number.parseInt(v));
const [majorB, minorB, patchB] = String(b).split('.').map(v => Number.parseInt(v));
if (majorA > majorB) {
return true;
}
if (majorB > minorA) {
return false;
}
if (minorA > minorB) {
return true;
}
if (minorB > minorA) {
return false;
}
if (patchA > patchB) {
return true;
}
if (patchB > patchA) {
return false;
}
return false;
};
assert(isGreater(versionB, versionA), 'version b should be greater.');
assert(isGreater(versionA, versionB), 'version b should be greater.');
my question is - is there a way to simplify the logic in the greaterThan function? This function is supposed to replicate the logic in semver.gt().
There's the standard npm semver version comparison library, but I have some simple logic to compare semver versions here:
const versionA = '14.8.3';
const versionB = '15.1.1';
const versionC = '15.1.2';
const semver = require('semver');
const assert = require('assert');
const isGreater = (a, b) => {
const [majorA, minorA, patchA] = String(a).split('.').map(v => Number.parseInt(v));
const [majorB, minorB, patchB] = String(b).split('.').map(v => Number.parseInt(v));
if (majorA > majorB) {
return true;
}
if (majorB > minorA) {
return false;
}
if (minorA > minorB) {
return true;
}
if (minorB > minorA) {
return false;
}
if (patchA > patchB) {
return true;
}
if (patchB > patchA) {
return false;
}
return false;
};
assert(isGreater(versionB, versionA), 'version b should be greater.');
assert(isGreater(versionA, versionB), 'version b should be greater.');
my question is - is there a way to simplify the logic in the greaterThan function? This function is supposed to replicate the logic in semver.gt().
Share Improve this question asked Apr 2, 2019 at 2:52 Alexander MillsAlexander Mills 100k165 gold badges531 silver badges908 bronze badges2 Answers
Reset to default 14You can use localeCompare
instead, with the numeric
option (with numeric
, comparison is such that "1" < "2" < "10"), which is exactly the logic you're looking for:
const versionA = '14.8.3';
const versionB = '15.1.1';
const versionC = '15.1.2';
const versionD = '15.1.10';
const versionE = '15.2.1';
const versionF = '15.11.1';
const isGreater = (a, b) => {
return a.localeCompare(b, undefined, { numeric: true }) === 1;
};
// first argument version comes later than second argument:
console.log(isGreater(versionB, versionA));
console.log(isGreater(versionC, versionB));
console.log(isGreater(versionD, versionC));
console.log(isGreater(versionE, versionD));
console.log(isGreater(versionF, versionE));
console.log('---');
// second comes before first:
console.log(isGreater(versionA, versionB));
// same, return value should be false:
console.log(isGreater(versionA, versionA));
Or, equivalently, you can pass the locale string
en-US-u-kn-true
as the second parameter instead of { numeric: true }
.
I believe this is logically the same and shorter, but not exactly stunning in it's simplicity
const parseInt = (v: string) : number => {
const num = Number.parseInt(v);
if(!(Number.isInteger(num) && num > 0)){
throw new Error('Could not parse positive integer from string')
}
return num;
};
const isGreater = (a: string, b: string) : boolean => {
const [majorA, minorA, patchA] = String(a).split('.').map(parseInt);
const [majorB, minorB, patchB] = String(b).split('.').map(parseInt);
if (majorA !== majorB) {
return majorA > majorB;
}
if (minorA !== minorB) {
return minorA > minorB;
}
return patchA > patchB;
};