I am trying to print an ASP.NET Image using the example here.
When I use the above example for a div, it works, but I can't adapt it to print anything else. How can I get it to print an Image? Do I wrap the Image in a div and change the ".text()" part in the script to something else?
I am trying to print an ASP.NET Image using the example here.
When I use the above example for a div, it works, but I can't adapt it to print anything else. How can I get it to print an Image? Do I wrap the Image in a div and change the ".text()" part in the script to something else?
5 Answers
Reset to default 9Because you're passing a wrong parameter to the printing function. Printing something in JavaScript is as easy as calling window.print(); method. To test it, simply use developer tools of your browser and write into its console:
window.print();
Now, when you want to print something specific, you have two ways:
- Create a special stylesheet for printing in the same page, which hides other elements and only shows your specified region.
- Or, open a new window, copy what you want there, then print it.
Now, what you can do is to write your own function:
function printImage(image)
{
var printWindow = window.open('', 'Print Window','height=400,width=600');
printWindow.document.write('<html><head><title>Print Window</title>');
printWindow.document.write('</head><body ><img src=\'');
printWindow.document.write(image.src);
printWindow.document.write('\' /></body></html>');
printWindow.document.close();
printWindow.print();
}
var image = document.getElementById('image');
printImage(image);
and you can also see this function in action here.
Just let the browser open popup, and also note that I only pass the src value of the image element to the new window.
Yes.
The following java script will help you to print an image in image control.
var printContent = document.getElementById('divImage');
var img = document.getElementById('imgMain');
var windowUrl = 'MyPage.aspx';
var uniqueName = new Date();
var windowName = "MyPage" + uniqueName.getTime();
printWindow = window.open(windowUrl, windowName, 'location=1,status=1,scrollbars=1,width=800,height=600');
printWindow.document.write("<div style='width:100%;'>");
printWindow.document.write("<img id='img' src='" + img.src + "'/>");
printWindow.document.write("</div>");
printWindow.document.close();
printWindow.focus();
printWindow.print();
printWindow.close();
return false;
this is better solution that also work fine in google chrome:
var printWindow = window.open('', 'Print Window', 'height=533,width=800');
printWindow.document.write('<html><head><title>Print Window</title>');
printWindow.document.write("<script src='script/jquery-1.11.3.min.js' type='text/javascript'><\/script>");
printWindow.document.write("<script type='text/javascript'>");
printWindow.document.write("var DoPrint = false;");
printWindow.document.write("$(document).ready(function () {");
printWindow.document.write("DoPrint = true;");
printWindow.document.write("});");
printWindow.document.write("<\/script>");
printWindow.document.write('</head><body ><img src=\'');
printWindow.document.write(document.getElementById('image').src);
printWindow.document.write('\' /></body></html>');
printWindow.document.close();
function Print() {
if (typeof printWindow.DoPrint != "undefined" && printWindow.DoPrint == true) {
clearInterval(PrintintervalNumber);
printWindow.print();
printWindow.close();
}
}
PrintintervalNumber = setInterval(Print, 1000);
Yep, instead of using .text(), you use .html() where you pass the <img /> (including the source of course) to the fake document ready for print.
Why not just make it this simple?
<input type="button" value="Print Div" onclick="PrintElem('<img src=myimage.jpg>')" />
and then call Popup like this: Popup(elem);
(you don't really need this Popup() function if you pass an image to print like this)