I use this regex
str = "asd34rgr888gfd98";
var p = str.match(/\d{2}/);
alert(p[0]);
butI not understood how can use variable as quantificator, that is how write this:
var number = 2;
var p = str.match(/\d{number}/);
P.S. I see this page JavaScript regex pattern concatenate with variable but not understood how use example from these posts, in my case.
I use this regex
str = "asd34rgr888gfd98";
var p = str.match(/\d{2}/);
alert(p[0]);
butI not understood how can use variable as quantificator, that is how write this:
var number = 2;
var p = str.match(/\d{number}/);
P.S. I see this page JavaScript regex pattern concatenate with variable but not understood how use example from these posts, in my case.
Share Improve this question edited May 23, 2017 at 11:44 CommunityBot 11 silver badge asked Oct 25, 2012 at 12:48 Oto ShavadzeOto Shavadze 42.8k55 gold badges164 silver badges245 bronze badges3 Answers
Reset to default 10You need to build your regex as a string and pass it to the RegExp
constructor:
var regexString = '\\d{' + number + '}';
var regex = new RegExp(regexString);
var p = str.match(regex);
Notice that when building a regex via a string, you need to add some extra escape characters to escape the string as well as the regex.
var number = "2"
var p = new RegExp("\\d{" + number + "}");
This should work:
var str = "asd34rgr888gfd98";
number = 3;
p = str.match(new RegExp('\\d{' + number + '}'));
alert(p[0]);