<div id="change" style="height:20px; width:100%; position: absolute; float:bottom; background-color:#000000">
</div> <br>
<select name="bgcolor" id="bgcolor" onchange="colorDiv()">
<option class="1" value=1> Grey
<option class="2" value=2> White
<option class="3" value=3> Blue
<option class="4" value=4> Cian
<option class="5" value=5> Green
</select> <br><br>
<p id="demo"></p>
<script>
function colorDiv(){
var selection = document.getElementById('bgcolor');
var div = document.getElementById( 'change' );
div.style.backgroundColor='green';
document.getElementById("demo").innerHTML =selection;
switch (selection){
case 1:
div.style.backgroundColor='grey';
case 2:
div.style.backgroundColor='white';
case 3:
div.style.backgroundColor='blue';
case 4:
div.style.backgroundColor='cian';
case 5:
div.style.backgroundColor='green';
}
</script>
Hi! I'm trying to change the background color of a div with js but it doesnt detect good the selected value, as i see when printing it on the parragraph. I've seen in multiple pages the procedure and it looks the same for me, but it actually does not work on my code. Can you see any mistakes? Thanks!!
<div id="change" style="height:20px; width:100%; position: absolute; float:bottom; background-color:#000000">
</div> <br>
<select name="bgcolor" id="bgcolor" onchange="colorDiv()">
<option class="1" value=1> Grey
<option class="2" value=2> White
<option class="3" value=3> Blue
<option class="4" value=4> Cian
<option class="5" value=5> Green
</select> <br><br>
<p id="demo"></p>
<script>
function colorDiv(){
var selection = document.getElementById('bgcolor');
var div = document.getElementById( 'change' );
div.style.backgroundColor='green';
document.getElementById("demo").innerHTML =selection;
switch (selection){
case 1:
div.style.backgroundColor='grey';
case 2:
div.style.backgroundColor='white';
case 3:
div.style.backgroundColor='blue';
case 4:
div.style.backgroundColor='cian';
case 5:
div.style.backgroundColor='green';
}
</script>
Hi! I'm trying to change the background color of a div with js but it doesnt detect good the selected value, as i see when printing it on the parragraph. I've seen in multiple pages the procedure and it looks the same for me, but it actually does not work on my code. Can you see any mistakes? Thanks!!
Share Improve this question asked Oct 29, 2013 at 18:38 Alvaro GomezAlvaro Gomez 3602 gold badges7 silver badges22 bronze badges4 Answers
Reset to default 10- Close your
option
tags. - Use
document.getElementById('bgcolor').value
- Don't forget to put
break
in eachcase
or you will end up with greendiv
everytime. - Use strings for your
case
conditions.
Amended Javascript:
function colorDiv() {
var selection = document.getElementById('bgcolor').value;
var div = document.getElementById('change');
div.style.backgroundColor = 'green';
document.getElementById("demo").innerHTML = selection;
switch (selection) {
case "1":
div.style.backgroundColor = 'grey';
break;
case "2":
div.style.backgroundColor = 'white';
break;
case "3":
div.style.backgroundColor = 'blue';
break;
case "4":
div.style.backgroundColor = 'cian';
break;
case "5":
div.style.backgroundColor = 'green';
break;
}
}
This working fiddle sums it up.
Also, the switch cases need a break statement after each one or the last one will be the one that you will see, in this case green. http://www.w3schools.com/js/js_switch.asp
<div id="change" style="height:20px; background-color:#000000">
change
</div>
<select name="bgcolor" id="bgcolor" onchange="colorDiv()">
<option class="1" value="0"> Grey</option>
<option class="2" value="1"> White </option>
<option class="3" value="2"> Blue</option>
<option class="4" value="3"> Cian</option>
<option class="5" value="4"> Green</option>
</select>
<p id="demo"></p>
<script>
function colorDiv(){
var selection = document.getElementById('bgcolor').selectedIndex;
var div = document.getElementById('change');
div.style.backgroundColor='green';
var colors = ["grey","white","blue","cian","green"];
document.getElementById("demo").innerHTML = colors[selection];
switch (selection){
case 0:
div.style.backgroundColor='grey';
break;
case 1:
div.style.backgroundColor='white';
break;
case 2:
div.style.backgroundColor='blue';
break;
case 3:
div.style.backgroundColor='cian';
break;
case 4:
div.style.backgroundColor='green';
break;
default:
div.style.backgroundColor='purple';
}
};
</script>
<html>
<body>
<button onclick="myFunction()">Try it</button>
<div style="width:100px; height:100px; float:left;border:1px solid #000;" id="demo"></div>
<script>
function myFunction() {
var latters = 'ABCDEF1234567890'.split("");
var color = '#';
for (var i=0; i < 6; i++)
{
color+=latters[Math.floor(Math.random() * 16)];
}
document.getElementById("demo").style.background = color ;
}
</script>
</body>
</html>