Hope somebody can help me out because I can't find any reference about this error.

I was working on this piece of code:

var xMin = d3.min(data, function(d) { return d.value; });
var xMax = d3.max(data, function(d) { return d.value; });

if (0 > xMin & 0 > xMax) {
  xMax = 0;
}

if (0 < xMin & 0 < xMax) { 
  xMin = 0;
}

x.domain(xMin, xMax).nice();
y.domain(data.map(function(d) { return d.label; }));

but I must have made some mistake cause now the loading blocks with the error message below in the web console:

"TypeError: t.map is not a function @ .v3.min.js:2

Hope somebody can help me out because I can't find any reference about this error.

I was working on this piece of code:

var xMin = d3.min(data, function(d) { return d.value; });
var xMax = d3.max(data, function(d) { return d.value; });

if (0 > xMin & 0 > xMax) {
  xMax = 0;
}

if (0 < xMin & 0 < xMax) { 
  xMin = 0;
}

x.domain(xMin, xMax).nice();
y.domain(data.map(function(d) { return d.label; }));

but I must have made some mistake cause now the loading blocks with the error message below in the web console:

"TypeError: t.map is not a function @ http://d3js.org/d3.v3.min.js:2

• javascript
• d3.js

• Should be x.domain([xMin, xMax]).nice(). – Lars Kotthoff Commented Jun 13, 2013 at 13:58
• thank you! That was exactly the problem! – mirba Commented Jun 13, 2013 at 14:12
• 1 Added as answer for reference. – Lars Kotthoff Commented Jun 13, 2013 at 14:22

2 Answers 2

.domain() takes an array as argument, i.e.

x.domain(xMin, xMax).nice();

should be

x.domain([xMin, xMax]).nice();

I had this error when I switched the mock data from an example.

   var dataset = d3.layout.stack()(["CountPending", "CountDenied"].map(function (type) {
            return data.map(function (d) {
                return { x: d.Name, y: +d[type] };
            });
        }));

In my dataset the example data was using ["pending","denied"] while my real data used the following keys ["CountPending", "CountDenied"]

Use the right keys!

While this might not help the OP, I hope it helps someone.