javascript - Get dynamic checkbox values with jQuery

I can't get the checked values of the dynamic check box. What am I doing wrong? /

Markup:

<html>
    <body>
      one<input type="checkbox" name='checkbox0' value="one_name" checked>
     two<input type="checkbox" name='checkbox1' value="one_name1">
     three<input type="checkbox" name='checkbox2' value="one_name2">
         <input type="button" id="envoyer" value="Envoyer Reponse"  /> 
    </body>
</html>

Javascript:

$('#envoyer').click(function(e){
    var myArray=new Array(4);
    for ( var j = 0; j < 3; j++){ 
        var check=$('input:checkbox[name=checkbox'+j+']').is(':checked');
        if(check==true)
            myArray[j]=$('input:checkbox[name=checkbox'+j+']').val();
    }
    alert('check '+" "+myArray[i]);
});

I can't get the checked values of the dynamic check box. What am I doing wrong? http://jsfiddle.net/hxfsB/17/

Markup:

<html>
    <body>
      one<input type="checkbox" name='checkbox0' value="one_name" checked>
     two<input type="checkbox" name='checkbox1' value="one_name1">
     three<input type="checkbox" name='checkbox2' value="one_name2">
         <input type="button" id="envoyer" value="Envoyer Reponse"  /> 
    </body>
</html>

Javascript:

$('#envoyer').click(function(e){
    var myArray=new Array(4);
    for ( var j = 0; j < 3; j++){ 
        var check=$('input:checkbox[name=checkbox'+j+']').is(':checked');
        if(check==true)
            myArray[j]=$('input:checkbox[name=checkbox'+j+']').val();
    }
    alert('check '+" "+myArray[i]);
});

Share Improve this question edited Jun 1, 2012 at 20:35 Jashwant 29k16 gold badges75 silver badges108 bronze badges asked Jun 1, 2012 at 20:20 MarwaInsat 2931 gold badge4 silver badges17 bronze badges

Look at your browser's JavaScript console in the developer tools. – David Thomas Commented Jun 1, 2012 at 20:25

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6 Answers 6

Sorted by: Reset to default 5

You have an error when outputting myArray in alert (there is no i variable defined).

However, your code can be better structured. Here is one solution:

$("#envoyer").click(function(e) {
    var myArray = [];
    $(":checkbox:checked").each(function() {
        myArray.push(this.value);
    });

    alert("Checked: " + myArray.join(","));
});

DEMO: http://jsfiddle.net/hxfsB/25/

You had an Uncaught ReferenceError: i is not defined; I've updated your fiddle here:

http://jsfiddle.net/hxfsB/24/

$('#envoyer').click(function(e){
    var myArray = new Array(3);
    for ( var j = 0; j < 3; j++) { 
        var check=$('input:checkbox[name=checkbox'+j+']').is(':checked');
        if(check==true)
            myArray[j]=$('input:checkbox[name=checkbox'+j+']').val();

        // Alert Current Selection //
        alert('check ' + " " + myArray[j] );
    }    
});

Keep in mind: undefined means the checkbox is NOT selected.

I hope this helps!

At your title suggests, if you want to get checked check-boxes values, you can do this,

Javascript:

$('#envoyer').click(function(e){
    $('input[type="checkbox"]:checked').each(function(){
        alert(this.value);
    })        
})

Markup

<html>
    <body>
      one<input type="checkbox" name='checkbox0' value="one_name" checked>
      two<input type="checkbox" name='checkbox1' value="one_name1">
      three<input type="checkbox" name='checkbox2' value="one_name2">
        <input type="button" id="envoyer" value="Envoyer Reponse"  /> 
    </body>
</html>

try this out : http://jsfiddle.net/hxfsB/27/

there is an issue with the selector

$('#envoyer').click(function(e){
    var myArray=new Array(3);

    $('input[type=checkbox]:checked').each(function(i) {
       myArray[i] = $(this).val();
       //alert($(this).val());
    });
});

The i in myArray[i] doesn't exist anywhere. You need to either put the alert inside the for loop and use myArray[j] or create a new for loop using i

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6 Answers 6

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