guys i have two cameras that is
-the web camera
-the laptop camera

i want to stream those camera in a website
i already have some reference
here is some code that is working on jsfiddle here

<video id="video" width="640" height="480" autoplay></video>
<button id="snap" class="sexyButton">Snap Photo</button>
<canvas id="canvas" width="640" height="480"></canvas>

<script>

    // Put event listeners into place
    window.addEventListener("DOMContentLoaded", function() {
        // Grab elements, create settings, etc.
        var canvas = document.getElementById("canvas"),
            context = canvas.getContext("2d"),
            video = document.getElementById("video"),
            videoObj = { "video": true },
            errBack = function(error) {
                console.log("Video capture error: ", error.code); 
            };

        // Put video listeners into place
        if(navigator.getUserMedia) { // Standard
            navigator.getUserMedia(videoObj, function(stream) {
                video.src = stream;
                video.play();
            }, errBack);
        } else if(navigator.webkitGetUserMedia) { // WebKit-prefixed
            navigator.webkitGetUserMedia(videoObj, function(stream){
                video.src = window.webkitURL.createObjectURL(stream);
                video.play();
            }, errBack);
        } else if(navigator.mozGetUserMedia) { // WebKit-prefixed
            navigator.mozGetUserMedia(videoObj, function(stream){
                video.src = window.URL.createObjectURL(stream);
                video.play();
            }, errBack);
        }

        // Trigger photo take
        document.getElementById("snap").addEventListener("click", function() {
            context.drawImage(video, 0, 0, 640, 480);
        });
    }, false);

</script>

that example can only connects and select 1 camera
i want to select and view two of my camera, any suggestion or solution guys?
you can also give me the JS fiddle

guys i have two cameras that is
-the web camera
-the laptop camera

i want to stream those camera in a website
i already have some reference
here is some code that is working on jsfiddle here

<video id="video" width="640" height="480" autoplay></video>
<button id="snap" class="sexyButton">Snap Photo</button>
<canvas id="canvas" width="640" height="480"></canvas>

<script>

    // Put event listeners into place
    window.addEventListener("DOMContentLoaded", function() {
        // Grab elements, create settings, etc.
        var canvas = document.getElementById("canvas"),
            context = canvas.getContext("2d"),
            video = document.getElementById("video"),
            videoObj = { "video": true },
            errBack = function(error) {
                console.log("Video capture error: ", error.code); 
            };

        // Put video listeners into place
        if(navigator.getUserMedia) { // Standard
            navigator.getUserMedia(videoObj, function(stream) {
                video.src = stream;
                video.play();
            }, errBack);
        } else if(navigator.webkitGetUserMedia) { // WebKit-prefixed
            navigator.webkitGetUserMedia(videoObj, function(stream){
                video.src = window.webkitURL.createObjectURL(stream);
                video.play();
            }, errBack);
        } else if(navigator.mozGetUserMedia) { // WebKit-prefixed
            navigator.mozGetUserMedia(videoObj, function(stream){
                video.src = window.URL.createObjectURL(stream);
                video.play();
            }, errBack);
        }

        // Trigger photo take
        document.getElementById("snap").addEventListener("click", function() {
            context.drawImage(video, 0, 0, 640, 480);
        });
    }, false);

</script>

that example can only connects and select 1 camera
i want to select and view two of my camera, any suggestion or solution guys?
you can also give me the JS fiddle

• javascript
• html5-video
• webcam
• getusermedia

• You can refer to this question - Enable rear camera with HTML5 – yushulx Commented Apr 2, 2014 at 5:54

2 Answers 2

You can create two different streams, one for each camera, and show them simultaneously in two <video> tags.

The list of available devices is available using navigator.mediaDevices.enumerateDevices(). After filtering the resulting list for only videoinputs, you have access to the deviceIds without needing permission from the user.

With getUserMedia you can then request a stream from the camera with id camera1Id using

navigator.mediaDevices.getUserMedia({
  video: {
    deviceId: { exact: camera1Id }
  }
});

The resulting stream can be fed into a <video> (referenced here by vid) by calling vid.srcObject = stream.

I have done this for two streams from two webcams simultaneously.

You cannot access two cameras simultaneously. The API would indicate otherwise, but something underlying seems to prevent it from working as expected. You can verify this by opening https://simpl.info/getusermedia/sources/ or http://googlechrome.github.io/webrtc/samples/web/content/getusermedia-source/ in two completely seperate windows, despite being able to select two streams only one is active at once - if you pick the same one in both windows, then it shows in both places. The only workaround I was able to do was to flip-flop between the two streams, then draw the video to a canvas. Doing this I was able to do captures at around 1 fps, unfortunately the camera resets between frames, on one of my cameras I had to put in a delay to allow the auto white balance to kick in to get a decent image.

function webcam() {
if (!navigator.getUserMedia) {
    navigator.getUserMedia = navigator.getUserMedia || navigator.webkitGetUserMedia || navigator.mozGetUserMedia || navigator.msGetUserMedia;
}

if (!navigator.getUserMedia) {
    return alert('getUserMedia not supported in this browser.');
}

var canvas = document.getElementById('canvas');
var context = canvas.getContext('2d');
var audioSource;
var cw = Math.floor(canvas.clientWidth / 2);
var ch = Math.floor(canvas.clientHeight/2);
//canvas.width = cw;
//canvas.height = ch;

//off dom video player
var video = document.createElement("video");
video.autoplay="autoplay";
video.addEventListener('playing', function(){
    //delay for settling...
    setTimeout(draw,1000,this,context,(currentSource*canvas.clientWidth/2),cw,ch);
},false);

function captureVideo() {
    console.log("Capturing " + currentSource,videosources[currentSource]);
    var mediaOptions = {
        audio: {
            optional: [{sourceId: audioSource}]
        },
        video: {
            optional: [
                {sourceId: videosources[currentSource].id}
            ]
        }};
    navigator.getUserMedia(mediaOptions, success, errorCallback);
}
var currentSource=0;
var videosources = [];
var lastStream;
function errorCallback(error){
    console.log("navigator.getUserMedia error: ", error);
}
function success(stream) {

    console.log("the stream" + currentSource,stream);
    video.src = window.URL.createObjectURL(stream);
    video.play();
    lastStream=stream;
}
function next(){

    if(lastStream){
        lastStream.stop();
    }
    video.src = "";
    if(currentSource < videosources.length-1){
        currentSource+=1;
    }
    else
    {
        currentSource=0;
    }
    captureVideo();
}
function draw(v,c,l,w,h) {
    if(v.paused || v.ended) return false;
    console.log("drawing",l)
    c.drawImage(v,l,0,w,h);
    setTimeout(next,500);
}

MediaStreamTrack.getSources(function (sourceInfos) {

    for (var i = 0; i != sourceInfos.length; ++i) {
        var sourceInfo = sourceInfos[i];
        if (sourceInfo.kind === 'audio') {
            console.log(sourceInfo.id, sourceInfo.label || 'microphone');
            audioSource=sourceInfo.id;

        } else if (sourceInfo.kind === 'video') {
            console.log(sourceInfo.id, sourceInfo.facing, sourceInfo.label || 'camera');
            videosources.push(sourceInfo);

        } else {
            console.log('Some other kind of source: ', sourceInfo);
        }
    }
console.log("sources",videosources)
    next();
});
}