Is there a way to extend express.Router ?

I tried this :

class Test extends express.Router() {

};

But express throws me an error.

Any solution ?

Is there a way to extend express.Router ?

I tried this :

class Test extends express.Router() {

};

But express throws me an error.

Any solution ?

• javascript
• node.js
• express

• Please, add the full stack trace to the question post. – gnerkus Commented Feb 6, 2016 at 15:55
• 5 maybe you got spelling wrong Routeur – Bek Commented Feb 6, 2016 at 17:02

5 Answers 5

The right way to do it:

class Test extends express.Router {
    constructor() {
        super();
        this.get('/', (req, res) => console.log('test'));
    }
};

When you write express.Router() (with parentheses) you already call the constructor and therefore you're trying to extend an object instead of class.

You can't do that because express.Router is a function. I haven't found how to extend a class with the function. But you can use an approach how this http://brianflove.com/2016/03/29/typescript-express-node-js/ or use standard approach with ES2015:

import * as express from 'express';

let router = express.Router();

/* GET home page. */
router.get('/', (req, res, next) => {
  res.render('index', { title: 'Express' });
});

export = router;

Maybe something like this:

function My_Router() {
    return express.Router.apply(this, arguments);
}

var myRouter = new My_Router();

Excuse me, I don't know English at all. Thanks to Google Translate ...

The constructor function should return a perfect (function, in fact) object of a router. You can add to this object, whatever you want, or change it as you wish. Each interface will have a new router object, of course.

It is also necessary to determine the prototype of the constructor function. This happens in line 6.

const Router = require("express").Router;

const myRouter = function () {

    const router = Router();
    Object.setPrototypeOf(Router, myRouter);

    router.myGet = function (path) {

        router.get.call(this, arguments);
        console.log("is my get function!!");

    };
    return router;
};

const router_custom = new myRouter();

router_custom.myGet("/", (req, res) => {

    res.send("hay!!");

});

May be something like this would help

 class YourController extends express.Router{
    constructor(){
        super()
        
        this.get("/", (req, res)=>{
            //do somthing
            res.send("return something");
        })
        
        this.get("/:id", (req, res)=>{
            //do something
            res.send("return something);
        })
    }
}

module.exports = new YourController();

Use It As :

const yourExtendedRouter = require("../controllers/YourController")

router.use("/base-url", yourExtendedRouter)