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PHP Symfony parse JSON response deserialize class constructor - Stack Overflow

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I am trying to parse this JSON $response body = {"low":{"networkFee":"0.00003"},"medium":{"networkFee":"0.0000428"},"high":{"networkFee":"0.00024"}}

my code:

class Low {
  private $networkFee;
}
class Medium {
  private $networkFee;
}
class High {
  private $networkFee;
}
class FeeClass{ 
  public function __construct(Low $low, Medium $medium, High $high) {
    $this->low = $low;
    $this->medium = $medium;
    $this->high = $high;
  }
}
$encoders = [new JsonEncoder()];
$normalizers = [new ObjectNormalizer()];
$serializer = new Serializer( $normalizers, $encoders );

$parsed = $serializer->deserialize((string)$response->getBody(), FeeClass::class, 'json');

var_dump("parsed:", $parsed);//I only get 3 NULL in $parsed

My dependencies:

"laravel/framework": "6.20.x",
"symfony/serializer": "5.1.x",

I am trying to parse this JSON $response body = {"low":{"networkFee":"0.00003"},"medium":{"networkFee":"0.0000428"},"high":{"networkFee":"0.00024"}}

my code:

class Low {
  private $networkFee;
}
class Medium {
  private $networkFee;
}
class High {
  private $networkFee;
}
class FeeClass{ 
  public function __construct(Low $low, Medium $medium, High $high) {
    $this->low = $low;
    $this->medium = $medium;
    $this->high = $high;
  }
}
$encoders = [new JsonEncoder()];
$normalizers = [new ObjectNormalizer()];
$serializer = new Serializer( $normalizers, $encoders );

$parsed = $serializer->deserialize((string)$response->getBody(), FeeClass::class, 'json');

var_dump("parsed:", $parsed);//I only get 3 NULL in $parsed

My dependencies:

"laravel/framework": "6.20.x",
"symfony/serializer": "5.1.x",
Share Improve this question edited Feb 6 at 16:49 Olivier 18.1k1 gold badge11 silver badges30 bronze badges asked Feb 6 at 16:18 RussoRusso 3,0023 gold badges40 silver badges51 bronze badges 3
  • 1 Why not just use json_decode? – aynber Commented Feb 6 at 16:26
  • because it is for my work... but let me try json_decode – Russo Commented Feb 6 at 16:35
  • 1 @aynber If you bypass the framework functionality you are forced to implement annoying manual checks (e.g. detect invalid JSON) and it's harder to get proper integration (how do you report errors?). – Álvaro González Commented 2 days ago
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1 Answer 1

Reset to default 1

A possibility is to make the $networkFee property public for Low, Medium and High:

require 'vendor/autoload.php';

use Symfony\Component\Serializer\Encoder\JsonEncoder;
use Symfony\Component\Serializer\Normalizer\ObjectNormalizer;
use Symfony\Component\Serializer\Serializer;

class Low {
  public $networkFee;
}

class Medium {
  public $networkFee;
}

class High {
  public $networkFee;
}

class FeeClass {
  private Low $low;
  private Medium $medium;
  private High $high;

  public function __construct(Low $low, Medium $medium, High $high) {
    $this->low = $low;
    $this->medium = $medium;
    $this->high = $high;
  }
}

$json = '{"low":{"networkFee":"0.00003"},"medium":{"networkFee":"0.0000428"},"high":{"networkFee":"0.00024"}}';

$encoders = [new JsonEncoder()];
$normalizers = [new ObjectNormalizer()];
$serializer = new Serializer( $normalizers, $encoders );
$parsed = $serializer->deserialize($json, FeeClass::class, 'json');
var_dump($parsed);

Output:

object(FeeClass)#31 (3) {
  ["low":"FeeClass":private]=>
  object(Low)#38 (1) {
    ["networkFee"]=>
    string(7) "0.00003"
  }
  ["medium":"FeeClass":private]=>
  object(Medium)#33 (1) {
    ["networkFee"]=>
    string(9) "0.0000428"
  }
  ["high":"FeeClass":private]=>
  object(High)#37 (1) {
    ["networkFee"]=>
    string(7) "0.00024"
  }
}

Alternatively you can add public constructors to Low, Medium and High:

class Low {
  private $networkFee;

  public function __construct($networkFee) {
      $this->networkFee = $networkFee;
  }
}

class Medium {
  private $networkFee;

  public function __construct($networkFee) {
      $this->networkFee = $networkFee;
  }
}

class High {
  private $networkFee;

  public function __construct($networkFee) {
      $this->networkFee = $networkFee;
  }
}
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