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javascript - Regular expression to allow comma and space delimited number list - Stack Overflow

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I want to write a regular expression using javascript or jquery to allow comma delimited list of numbers OR space delimited numbers OR comma followed by a space delimited numbers OR a combination of any of the above ex anything that is not a digit, space or comma must be rejected

SHOULD PASS 111,222,333 111 222 333 111, 222, 333 111,222,333 444 555 666, 111, 222, 333,

should NOT pass: 111,222,3a 3a 111 222 3a etc etc

I tried the code below they seemed to work however when I typed 3a as a number, it PASSED!!! How? I cannot understand how my code allowed that letter to pass.

I want to reject anything that is not a space, comma or digit

or is there a better way to do this without regular expressions? I looked in google and did not find any answer.

Thank you in advance for any help.

var isNumeric = /[\d]+([\s]?[,]?[\d])*/.test(userInput);
var isNumeric = /^[\d\s,]*/.test(userInput);    
var isNumeric = /^[\d]*[\s,]*/.test(userInput); 
var isNumeric = /^[\d\s,]*/.test(userInput);    
var isNumeric = /\d+\s*,*/.test(userInput); 

if (isNumeric == false) {
    alert(isNumeric);
  return false;
}
else
      alert('is Numeric!!!');

I want to write a regular expression using javascript or jquery to allow comma delimited list of numbers OR space delimited numbers OR comma followed by a space delimited numbers OR a combination of any of the above ex anything that is not a digit, space or comma must be rejected

SHOULD PASS 111,222,333 111 222 333 111, 222, 333 111,222,333 444 555 666, 111, 222, 333,

should NOT pass: 111,222,3a 3a 111 222 3a etc etc

I tried the code below they seemed to work however when I typed 3a as a number, it PASSED!!! How? I cannot understand how my code allowed that letter to pass.

I want to reject anything that is not a space, comma or digit

or is there a better way to do this without regular expressions? I looked in google and did not find any answer.

Thank you in advance for any help.

var isNumeric = /[\d]+([\s]?[,]?[\d])*/.test(userInput);
var isNumeric = /^[\d\s,]*/.test(userInput);    
var isNumeric = /^[\d]*[\s,]*/.test(userInput); 
var isNumeric = /^[\d\s,]*/.test(userInput);    
var isNumeric = /\d+\s*,*/.test(userInput); 

if (isNumeric == false) {
    alert(isNumeric);
  return false;
}
else
      alert('is Numeric!!!');
Share Improve this question asked Jul 4, 2013 at 14:15 javafunjavafun 1952 gold badges2 silver badges8 bronze badges 3
  • [\d] is exactly the same as just \d without the [] – Pointy Commented Jul 4, 2013 at 14:19
  • Also the answer to your question is that you're leaving off $ at the end of the regular expression, which means that the matched pattern may be followed by any subsequent characters. – Pointy Commented Jul 4, 2013 at 14:19
  • 1 Your test case above will only be testing the final regex. – Grim... Commented Jul 4, 2013 at 14:20
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3 Answers 3

Reset to default 10

Would the regular expression ^[\d,\s]+$ not do the trick?

Try this Regex... Click to view your demo

^[0-9 _ ,]*$

Guess ^(\d+[, ]+)*$ should do it.

Explanation: A group containing one or more digits followed by at least one space or comma. Group may be repeated any number of times.

It's doesn't handle everything though, like failing when there are commas without a number between (if that's what you want).

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