Say I have an array-ish container of decimal numbers. I want the sum. In Python I would do this:
x = [1.2, 3.4, 5.6]
sum(x)
Is there a similarly concise way to do this in JavaScript?
Say I have an array-ish container of decimal numbers. I want the sum. In Python I would do this:
x = [1.2, 3.4, 5.6]
sum(x)
Is there a similarly concise way to do this in JavaScript?
Share Improve this question edited Aug 20, 2010 at 8:49 Peter Mortensen 31.6k22 gold badges110 silver badges133 bronze badges asked Jul 30, 2010 at 1:48 twnealetwneale 2,9465 gold badges29 silver badges37 bronze badges2 Answers
Reset to default 13Another approach, a simple iterative function:
function sum(arr) {
var result = 0, n = arr.length || 0; //may use >>> 0 to ensure length is Uint32
while(n--) {
result += +arr[n]; // unary operator to ensure ToNumber conversion
}
return result;
}
var x = [1.2, 3.4, 5.6];
sum(x); // 10.2
Yet another approach using Array.prototype.reduce
:
var arr = [1.2, 3.4, 5.6];
arr.reduce(function (a, b) { return a + b; }, 0); // 10.2
The reduce
method is part of the ECMAScript 5th Edition standard, is widely available, but is not on IE <= 8, however an implementation cay be included from the the Mozilla Dev Center I linked.
I guess there's none... but you can make one on javascript
Array.prototype.sum = function() {
return (! this.length) ? 0 : this.slice(1).sum() +
((typeof this[0] == 'number') ? this[0] : 0);
};
use it as,
[1,2,3,4,5].sum() //--> returns 15
[1,2,'',3,''].sum() //--> returns 6
[].sum() //--> returns 0
x = [1.2, 3.4, 5.6]
x.sum(); // returns 10.2
demo
Okay as pointed out in the comment, you can also do it as non-recursive way
Array.prototype.sum = function() {
var num = 0;
for (var i = 0; i < this.length; i++) {
num += (typeof this[i] == 'number') ? this[i] : 0;
}
return num;
};
Another way to do it, through function..
function sum(arr) {
var num = 0;
for (var i = 0; i < arr.length; i++) {
num += (typeof arr[i] == 'number') ? arr[i] : 0;
}
return num;
};
use it as,
sum([1,2,3,4,5]) //--> returns 15
x = [1.2, 3.4, 5.6]
sum(x); // returns 10.2