Let's say we have an array of objects like:
var fruits = [ {name:"banana", weight:150},{name:"apple", weight:95},{name:"orange", weight:160},{name:"kiwi", weight:80} ];
I want to populate a "heavy_fruits" array with items from the "fruits" array above which weight is > 100. Here is my code:
var heavy_fruits = [];
myfruit = {};
fruits.forEach(function(item,index) {
if ( item.weight > 100 ) {
myfruit ["name"] = item.name;
myfruit ["weight"] = item.weight;
}
heavy_fruits.push(myfruit);
});
However it shows: name:"orange", weight:160 name:"orange", weight:160 name:"orange", weight:160 name:"orange", weight:160
I know this is an issue with mixing closures and loops... but I read an article (/) explaining that I would avoid this kind of issue using a forEach loop instead of the classic for loop.
I know I can use array methods like filter(), etc. but I'm asking that on purpose since I'm actually having troubles with a much bigger function that I cannot expose here... So I tried to summarize and simplify my issue description with "fruits".
Let's say we have an array of objects like:
var fruits = [ {name:"banana", weight:150},{name:"apple", weight:95},{name:"orange", weight:160},{name:"kiwi", weight:80} ];
I want to populate a "heavy_fruits" array with items from the "fruits" array above which weight is > 100. Here is my code:
var heavy_fruits = [];
myfruit = {};
fruits.forEach(function(item,index) {
if ( item.weight > 100 ) {
myfruit ["name"] = item.name;
myfruit ["weight"] = item.weight;
}
heavy_fruits.push(myfruit);
});
However it shows: name:"orange", weight:160 name:"orange", weight:160 name:"orange", weight:160 name:"orange", weight:160
I know this is an issue with mixing closures and loops... but I read an article (http://zsoltfabok.com/blog/2012/08/javascript-foreach/) explaining that I would avoid this kind of issue using a forEach loop instead of the classic for loop.
I know I can use array methods like filter(), etc. but I'm asking that on purpose since I'm actually having troubles with a much bigger function that I cannot expose here... So I tried to summarize and simplify my issue description with "fruits".
Share Improve this question edited Aug 9, 2016 at 15:53 Albzi 15.6k6 gold badges48 silver badges67 bronze badges asked Aug 9, 2016 at 15:52 nadirnadir 1,3234 gold badges12 silver badges21 bronze badges 5 |4 Answers
Reset to default 8var heavy_fruits = [];
myfruit = {}; // here's your object
fruits.forEach(function(item,index) {
if ( item.weight > 100 ) {
myfruit ["name"] = item.name;
myfruit ["weight"] = item.weight; // you modify it's properties
}
heavy_fruits.push(myfruit); // you push it to the array
});
You end up with an array [myfruit, myfruit, myfruit, myfruit]
.
Now if you modify myfruit
anywhere in the code, the change will be visible in every single occurence of myfruit
. Why?
Because you are modifying the referenece to the object. In this example, your array stores just copies of your object. And if you change one of it, every single one will change, because they are all references.
To fix this with each iteration you should be creating a new object and then doing some stuff on it.
BTW, as a matter of fact, your if
could just be like this:
if ( item.weight > 100 ) {
heavy_fruits.push(item); // if `item` only has `name` and `weight` properties
}
fruits.forEach(function (item, index) {
if (item.weight > 100) {
myfruit = {};
myfruit["name"] = item.name;
myfruit["weight"] = item.weight;
heavy_fruits.push(myfruit);
}
});
The shorter would use filter
var heavy_fruits = fruits.filter(x => x.weight > 100);
But if you realy want to use forEach do this way
var heavy_fruits = [];
fruits.forEach(x => {if(x.weight > 100) heavy_fruits.push(x)} );
forEach
is not only an array method, so you might encounter it with DOM list of elements, that may have no map method.
As forEach
is unfortunately not returning an array (as opposed to map
), it's usage is pushing to an array you should predefine, as with the previous answers here.
var values = Array();
var subelem = document.querySelectorAll('#elemid subelem');
values.push(subelem.value);
myfruit
is referencing to same object. Movemyfruit = {};
in theforEach
callback. And I'll suggest to usefilter
asvar heavy_fruits = fruits.filter(f => f.weight > 100);
. – Tushar Commented Aug 9, 2016 at 15:53forEach
has got <= 2% use case. For this particular case you should use eitherfilter
orreduce
. – Redu Commented Aug 9, 2016 at 19:26forEach
. – Kate Commented Dec 30, 2019 at 14:38