Why in my js code can just with one click on name:check_all
checking all checkboxes?
HTML:
<div id="ss">
<input type="checkbox" name="check_all">
</div>
<input type="checkbox" name="checked" class="idRow">
<input type="checkbox" name="checked" class="idRow">
<input type="checkbox" name="checked" class="idRow">
<input type="checkbox" name="checked" class="idRow">
<input type="checkbox" name="checked" class="idRow">
<input type="checkbox" name="checked" class="idRow">
<input type="checkbox" name="checked" class="idRow">
<input type="checkbox" name="checked" class="idRow">
jQuery:
$(document).on('click change','input[name="check_all"]',function() {
var checkboxes = $('.idRow');
if($(this).is(':checked')) {
checkboxes.attr("checked" , true);
} else {
checkboxes.attr ( "checked" , false );
}
});
DEMO: /
My jQuery version is 1.9.
How can fix it?
Why in my js code can just with one click on name:check_all
checking all checkboxes?
HTML:
<div id="ss">
<input type="checkbox" name="check_all">
</div>
<input type="checkbox" name="checked" class="idRow">
<input type="checkbox" name="checked" class="idRow">
<input type="checkbox" name="checked" class="idRow">
<input type="checkbox" name="checked" class="idRow">
<input type="checkbox" name="checked" class="idRow">
<input type="checkbox" name="checked" class="idRow">
<input type="checkbox" name="checked" class="idRow">
<input type="checkbox" name="checked" class="idRow">
jQuery:
$(document).on('click change','input[name="check_all"]',function() {
var checkboxes = $('.idRow');
if($(this).is(':checked')) {
checkboxes.attr("checked" , true);
} else {
checkboxes.attr ( "checked" , false );
}
});
DEMO: http://jsfiddle.net/KdaZr/
My jQuery version is 1.9.
How can fix it?
Share Improve this question asked Feb 17, 2013 at 20:45 Taylor GomezTaylor Gomez 3301 gold badge5 silver badges22 bronze badges4 Answers
Reset to default 15Use prop
method. When your markup is rendered attributes become properties of the elements, using JavaScript you should modify properties of the element.
$(document).on('change','input[name="check_all"]',function() {
$('.idRow').prop("checked" , this.checked);
});
http://jsfiddle.net/GW64e/
Note that if input[name="check_all"]
is not generated dynamically there is no need to delegate the event.
Use .prop
, not .attr
, to change properties of elements. .attr
is for HTML attributes.
http://jsfiddle.net/KdaZr/1/
fix is as follow:-
$(document).on('click change','input[name="check_all"]',function() {
var checkboxes = $('.idRow');
if($(this).is(':checked')) {
checkboxes.each(function(){
this.checked = true;
});
} else {
checkboxes.each(function(){
this.checked = false;
});
}
});
A complete solution select || deselect checkbox jQuery :
$(document).ready(function() {
$("#checkedAll").change(function(){
if(this.checked){
$(".checkSingle").each(function(){
this.checked=true;
})
}else{
$(".checkSingle").each(function(){
this.checked=false;
})
}
});
$(".checkSingle").click(function () {
if ($(this).is(":checked")){
var isAllChecked = 0;
$(".checkSingle").each(function(){
if(!this.checked)
isAllChecked = 1;
})
if(isAllChecked == 0){ $("#checkedAll").prop("checked", true); }
}
else {
$("#checkedAll").prop("checked", false);
}
});
});
Html should be :
Single check box on checked three checkbox will be select and deselect.
<input type="checkbox" name="checkedAll" id="checkedAll"></input>
<input type="checkbox" name="checkAll" class="checkSingle"></input>
<input type="checkbox" name="checkAll" class="checkSingle"></input>
<input type="checkbox" name="checkAll" class="checkSingle"></input>
Hope this helps to someone as it did for me.