最新消息:雨落星辰是一个专注网站SEO优化、网站SEO诊断、搜索引擎研究、网络营销推广、网站策划运营及站长类的自媒体原创博客

javascript - Help with regexp replacing every second comma in the string - Stack Overflow

programmeradmin2浏览0评论

I have a string of that displays like this....

1235, 3, 1343, 5, 1234, 1

I need to replace every second comma with a semicolon

i.e.

1235, 3; 1343, 5; 1234, 1

the string length will always be different but will follow the same pattern as the above i.e. digits comma space digits comma space, etc.

how can I do this with javascript? Is it possible?

Thanks, Mike

I have a string of that displays like this....

1235, 3, 1343, 5, 1234, 1

I need to replace every second comma with a semicolon

i.e.

1235, 3; 1343, 5; 1234, 1

the string length will always be different but will follow the same pattern as the above i.e. digits comma space digits comma space, etc.

how can I do this with javascript? Is it possible?

Thanks, Mike

Share Improve this question edited May 20, 2009 at 18:14 Motti 115k56 gold badges194 silver badges273 bronze badges asked May 20, 2009 at 18:12 michael duvallmichael duvall 831 silver badge4 bronze badges 1
  • 2 Thank you all very much, I have learned quite a bit from these examples. – michael duvall Commented May 21, 2009 at 15:07
Add a comment  | 

6 Answers 6

Reset to default 8
'1235, 3, 1343, 5, 1234, 1'.replace(/([0-9]+),\s([0-9]+),\s/g, '$1, $2; ')
var s = '1235, 3, 1343, 5, 1234, 1';
var result = s.replace(/(,[^,]*),/g,"$1;");
var s='1235, 3, 1343, 5, 1234, 1';

s=s.replace(/([^,]+,[^,]+),/g,'$1;')

match anything that is not a comma, followed by a comma, followed by anything that is not a comma, and a comma.

replace everthing inside the parens (which doesn't include the last comma) with itself ('$1'), and add a semicolon in place of that comma.

How about:

var regex = /(\d+),\s(\d+),\s/g;
var str = '1235, 3, 1343, 5, 1234, 1'; 
alert(str.replace(regex, '$1, $2; ')); // 1235, 3; 1343, 5; 1234, 1
var myregexp = /(\d+,\s\d+),/g;
result = subject.replace(myregexp, "$1;");

var foo = "1235,3,1343,5,1234,1".replace(/(.\*?),(.\*?),/g, "$1,$2;");

console.log(foo)

发布评论

评论列表(0)

  1. 暂无评论