In my poker app I have an array of hands, each hand being array of randomly selected card objects with value and suit:
[ [ { value: 5, suit: 's' },
{ value: 4, suit: 's' },
{ value: 6, suit: 'c' },
{ value: 11, suit: 'd' },
{ value: 12, suit: 'c' } ],
[ { value: 9, suit: 'd' },
{ value: 12, suit: 'h' },
{ value: 8, suit: 'c' },
{ value: 12, suit: 's' },
{ value: 2, suit: 's' } ],
[ { value: 4, suit: 'h' },
{ value: 6, suit: 's' },
{ value: 10, suit: 'c' },
{ value: 3, suit: 'd' },
{ value: 7, suit: 'd' } ] ]
To prepare the hands for evaluation I want to use Array.reduce to return an array of hand objects. So the output would be:
[
{
values: [5, 4, 6, 11, 12],
suits: ['s', 's', 'c', 'd', 'c']
},
{
values: [9, 12, 8, 12, 2],
suits: ['d', 'h', 'c', 's', 's']
},
{
values: [4, 6, 10, 3, 7],
suits: ['h', 's', 'c', 'd', 'd']
}
]
I tried implementing this with nested forEach's, but its failing and I don't know why. I have two console.log's within which output as expected, but in the end hands is identical to the input.
let temp = []
hands.forEach((el) => {
temp = el
el = {}
el.values = []
el.suits = []
console.log(el) //expected output
temp.forEach((obj) => {
el.values.push(obj.value)
el.suits.push(obj.suit)
console.log(el) //expected output
})
})
console.log(hands) //same as original
In my poker app I have an array of hands, each hand being array of randomly selected card objects with value and suit:
[ [ { value: 5, suit: 's' },
{ value: 4, suit: 's' },
{ value: 6, suit: 'c' },
{ value: 11, suit: 'd' },
{ value: 12, suit: 'c' } ],
[ { value: 9, suit: 'd' },
{ value: 12, suit: 'h' },
{ value: 8, suit: 'c' },
{ value: 12, suit: 's' },
{ value: 2, suit: 's' } ],
[ { value: 4, suit: 'h' },
{ value: 6, suit: 's' },
{ value: 10, suit: 'c' },
{ value: 3, suit: 'd' },
{ value: 7, suit: 'd' } ] ]
To prepare the hands for evaluation I want to use Array.reduce to return an array of hand objects. So the output would be:
[
{
values: [5, 4, 6, 11, 12],
suits: ['s', 's', 'c', 'd', 'c']
},
{
values: [9, 12, 8, 12, 2],
suits: ['d', 'h', 'c', 's', 's']
},
{
values: [4, 6, 10, 3, 7],
suits: ['h', 's', 'c', 'd', 'd']
}
]
I tried implementing this with nested forEach's, but its failing and I don't know why. I have two console.log's within which output as expected, but in the end hands is identical to the input.
let temp = []
hands.forEach((el) => {
temp = el
el = {}
el.values = []
el.suits = []
console.log(el) //expected output
temp.forEach((obj) => {
el.values.push(obj.value)
el.suits.push(obj.suit)
console.log(el) //expected output
})
})
console.log(hands) //same as original
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edited Dec 20, 2016 at 17:33
Barmar
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asked Dec 20, 2016 at 1:12
Jackson LenhartJackson Lenhart
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4 Answers
Reset to default 16You have to be thinking about the shape of your input data (DATA
) and output (DATA'
)
Note 1:1 relationship between HAND
and HAND'
meaning we will use Array.prototype.map
for one transformation. On the other hand, CARD
has a N:1 relationship with HAND'
meaing we will use Array.prototype.reduce
for that transformation
So keep in mind while we're working, we will be doing a map and a reduce
const data =
[ [ { value: 5, suit: 's' },
{ value: 4, suit: 's' },
{ value: 6, suit: 'c' },
{ value: 11, suit: 'd' },
{ value: 12, suit: 'c' } ],
[ { value: 9, suit: 'd' },
{ value: 12, suit: 'h' },
{ value: 8, suit: 'c' },
{ value: 12, suit: 's' },
{ value: 2, suit: 's' } ],
[ { value: 4, suit: 'h' },
{ value: 6, suit: 's' },
{ value: 10, suit: 'c' },
{ value: 3, suit: 'd' },
{ value: 7, suit: 'd' } ] ]
let output =
data.map(cards =>
cards.reduce(({values, suits}, {value, suit}) => ({
values: [...values, value],
suits: [...suits, suit]
}), {values: [], suits: []}))
console.log(output)
Now of course that looks a little dense so it would be nice if we could dial down the complexity a bit. By making some curried adapters for map
and reduce
we can express a function that performs your transformation quite nicely
const data =
[ [ { value: 5, suit: 's' },
{ value: 4, suit: 's' },
{ value: 6, suit: 'c' },
{ value: 11, suit: 'd' },
{ value: 12, suit: 'c' } ],
[ { value: 9, suit: 'd' },
{ value: 12, suit: 'h' },
{ value: 8, suit: 'c' },
{ value: 12, suit: 's' },
{ value: 2, suit: 's' } ],
[ { value: 4, suit: 'h' },
{ value: 6, suit: 's' },
{ value: 10, suit: 'c' },
{ value: 3, suit: 'd' },
{ value: 7, suit: 'd' } ] ]
const map = f => xs => xs.map(f)
const reduce = f => y => xs => xs.reduce(f, y)
const handAppendCard = ({values, suits}, {value, suit}) => ({
values: [...values, value],
suits: [...suits, suit]
})
const makeHands =
map (reduce (handAppendCard) ({values:[], suits:[]}))
let output = makeHands (data)
console.log(output)
That's just one way to approach the problem. I hope you were able to learn something from it ^_^
There you go - a solution using nested Array.prototype.reduce
functions:
var array=[[{value:5,suit:'s'},{value:4,suit:'s'},{value:6,suit:'c'},{value:11,suit:'d'},{value:12,suit:'c'}],[{value:9,suit:'d'},{value:12,suit:'h'},{value:8,suit:'c'},{value:12,suit:'s'},{value:2,suit:'s'}],[{value:4,suit:'h'},{value:6,suit:'s'},{value:10,suit:'c'},{value:3,suit:'d'},{value:7,suit:'d'}]];
var result = array.reduce(function(p, c) {
p.push(c.reduce(function(a, b) {
a.values.push(b.value);
a.suits.push(b.suit);
return a;
}, {values: [],suits: []}));
return p;
},[]);
console.log(result);
.as-console-wrapper {top: 0;max-height: 100%!important;}
You can use reduce flat
to extract nested arrays. If you pass Infinity
, no matter how deep they are, they'll be extracted.
const result = flatten([1,2,[3,4],[5,6,7]]) // result: [1,2,3,4,5,6,7]
Everything becomes one-dimensional array
Here's a simple solution with string concat
and reduce
. You could try something like:
var reduced = [];
//here a is your initial array
for(var i=0; i<a.length;i++){
reduced.push(a[i].reduce(function(prev,curr){
var obj={value:prev.value+','+curr.value,suit:prev.suit+','+curr.suit};return obj}));
}
console.log(reduced)
EDIT: As per @Barmar comment this returns string. If you want an array you could do:
for(var i=0; i<a.length;i++){
var tempElm =a[i].reduce(function(prev,curr) {
var obj= {value:prev.value+','+curr.value,suit:prev.suit+','+curr.suit};return obj});
tempElm['value'] = tempElm['value'].split();
tempElm['suit']= tempElm['suit'].split();
reduced.push(tempElm);
}
console.log(reduced)
EDIT 2: With the fair criticism for the above fix (which adds an over head of converting string to array) You could directly create array instead as follows:
var reduced = [];
for(var i=0; i<a.length;i++){
var valArray = []; var suitArray=[];
var tempElm = a[i].reduce(function(prev,curr) {
valArray.push(curr.value);suitArray.push(curr.suit);
var obj= {value:valArray,suit:suitArray};
return obj;
},null);
console.log(reduced)
reduce
? It seems like it would be simpler usingforEach
. – Barmar Commented Dec 20, 2016 at 2:02el
is a variable local to the function, it gets reset to{}
each time through theforEach
loop. Your code never modifieshands
. – Barmar Commented Dec 20, 2016 at 17:35