boost
本文介绍了boost-python:如何提供自定义构造函数包装函数?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述我正在使用boost-python为名为CppClass的C ++类创建python绑定.必要时，我可以通过对参数进行预处理的小型包装函数将调用路由到普通"成员函数(例如，从python args中提取C ++类型)，例如:
I'm using boost-python to create python bindings for a C++ class named CppClass. When necessary, I can route calls to "normal" member functions through little wrapper functions that preprocess the arguments (e.g. extract C++ types from the python args), like so:
class CppClass{public: CppClass(SpecialParameters p); void doSomething(int x, float y);};using namespace boost::python; // For extract, tuple, init, class_, etc.class WrapperFuncs{public: static void doSomething(CppClass & c, tuple t) { // Special extraction: Convert python arg ( a tuple) into C++ args. int x = extract<int>(t.attr("__getitem__")(0)); float y = extract<float>(t.attr("__getitem__")(1)); c.doSomething(x,y); }};class_<CppClass, boost::shared_ptr<CppClass> > ("CppClass", init<SpecialParameters>()) .def("doSomething", &WrapperFuncs::doSomething, (arg("t")))但是对于CppClass 构造函数，我该怎么做?
But how do I do the same for the CppClass constructor?
推荐答案使用no_init，然后使用boost::python::make_constructor()使用.def表示__init__.
Use no_init followed by a .def for __init__ using boost::python::make_constructor().
class WrapperFuncs{public: static boost::shared_ptr<CppClass> initWrapper( object const & p ) { SpecialParameters sp = ... // do complicated extraction here. return boost::shared_ptr<CppClass>( new CppClass(sp) ); } static void doSomething(CppClass & c, tuple t) { /*...*/ }};class_<CppClass, boost::shared_ptr<CppClass> > ("CppClass", no_init) .def("__init__", make_constructor(&WrapperFuncs::initWrapper)) .def("doSomething", &WrapperFuncs::doSomething, (arg("t")))Python Wiki的本部分解释了如何执行此操作，但是它对我不太有用，因为它没有提到no_init.就我而言，no_init是必需的.
This section of the python wiki explains how to do this, but it didn't quite work for me because it didn't mention no_init. In my case, no_init was required.
boost