将自定义中间件放在自定义next.js服务器的链中?
我正在尝试将自定义中间件添加到自定义next.js服务器。但是我没有特定的路径模式可以将我的中间件绑定到,因为这些URL是由我们的CMS生成的,几乎可以是任何东西。所以我想在链中添加我的中间件,可以这么说。作为最后的全能。但我找不到任何关于如何实现这一目标的文档。
我试图简单地将我的中间件放在最后,但这导致它从未被调用。
工作但丑陋,而不是未来证明:
//Our custom middleware first
server.get('*', [customMiddleware, standardMiddleware])
...
const customMiddleware = async function (req, res, next) {
const parsedUrl = parse(req.url, true)
const { pathname, query } = parsedUrl
console.log("Custom middleware. pathname: " + pathname)
if (pathname.startsWith("/babel/") || pathname.startsWith("/_next/") || pathname.startsWith("/static/") ...etc) {
return next()
}
///Custom logic here...
}
const standardMiddleware = function (req, res, next) {
const parsedUrl = parse(req.url, true)
const { pathname, query } = parsedUrl
console.log("Standard middleware. pathname: " + pathname)
return handle(req, res)
}
不工作:
//Our custom middleware last
server.get('*', [standardMiddleware, customMiddleware])
...
const standardMiddleware = function (req, res, next) {
const parsedUrl = parse(req.url, true)
const { pathname, query } = parsedUrl
console.log("Standard middleware. pathname: " + pathname)
return handle(req, res)
}
const customMiddleware = async function (req, res, next) {
const parsedUrl = parse(req.url, true)
const { pathname, query } = parsedUrl
console.log("Custom middleware. pathname: " + pathname)
///Custom logic here...
}
当我运行上面标记为“不工作”的代码时,我希望next.js处理它可以处理的所有请求,然后回退到customMiddleware以获取所有其他请求。实际发生的事情是它永远不会回退到customMiddleware,它只是为未知路径返回404。
更新2019-02-13
由于目前的NextJS代码似乎不可能,因此我将其添加为feature request。
回答如下:为了说明我上面的评论:
const standardMiddleware = function (req, res, next) { // next is a callback argument here
const parsedUrl = parse(req.url, true)
const { pathname, query } = parsedUrl
console.log("Standard middleware. pathname: " + pathname)
return handle(req, res, next); // pass it along
}
...
function handle(req, res, next) {
...
if (noRouteEventuallyMatched) {
// res.status(404).sendFile('/path/to/my404.html');
next(); // instead of setting res, call next so that the next element in the chain is tried
}
}