我有一个Python对象的列表，我想通过对象本身的属性来排序。列表如下：
>>> ut [< Tag：128>，< Tag：2008>，< Tag：<>，< Tag：actionscript> ;,< Tag：addresses>，< Tag ：aes>，< Tag：ajax> ...]每个对象都有一个计数：
$ b b >>> ut [1] .count 1L我需要按计数对列表排序
我已经看过几种方法，但我正在寻找Python的最佳实践。
＃对列表进行排序... ut.sort（key = lambda x：x.count，reverse = true） ＃要返回一个新的列表，使用sorted（）内置函数... newlist = sorted（ut，key = lambda x：x.count，reverse = True）
更多 sort by keys»
I've got a list of Python objects that I'd like to sort by an attribute of the objects themselves. The list looks like:
>>> ut [<Tag: 128>, <Tag: 2008>, <Tag: <>, <Tag: actionscript>, <Tag: addresses>, <Tag: aes>, <Tag: ajax> ...]Each object has a count:
>>> ut[1].count 1LI need to sort the list by number of counts descending.
I've seen several methods for this, but I'm looking for best practice in Python.
解决方案 # To sort the list in place... ut.sort(key=lambda x: x.count, reverse=True) # To return a new list, use the sorted() built-in function... newlist = sorted(ut, key=lambda x: x.count, reverse=True)More on sorting by keys »