I am trying to capture all the digits of an input string. The string can also contain other characters like letters so I can't simply do [0-9]+.
I've tried /[0-9]/g but this returns all digits as an array.
How do you capture, or match, every instance of a digit and return as a string?
I am trying to capture all the digits of an input string. The string can also contain other characters like letters so I can't simply do [0-9]+.
I've tried /[0-9]/g but this returns all digits as an array.
How do you capture, or match, every instance of a digit and return as a string?
Share Improve this question edited Feb 15, 2013 at 20:01 Rohit Jain 213k45 gold badges414 silver badges533 bronze badges asked Feb 15, 2013 at 19:52 CodyBugsteinCodyBugstein 23.4k67 gold badges225 silver badges381 bronze badges 2- What language are you using? – Rohit Jain Commented Feb 15, 2013 at 19:53
- JavaScript. I updated the question – CodyBugstein Commented Feb 15, 2013 at 19:57
3 Answers
Reset to default 3Just replace all the non-digits from the original string:
var s = "foo 123 bar 456";
var digits = s.replace(/\D+/g, "");
The other solutions are better, but to do it just as you asked, you simply need to join the array.
var str = "this 1 string has 2 digits";
var result = str.match(/[0-9]+/g).join(''); // 12
You can replace all the non-digits character rather than extracting the digits:
var str = "some string 22 with digits 2131";
str = str.replace(new RegExp("\D","g"),"");
\D is same as [^\d].