I am trying to pass in two variables to a JavaScript function: the input itself and the user id. I call the function using the onclick attribute of the input.

 echo "<input type = 'submit' class = 'replyButton' id = 'replyButton'
 value = 'reply' onclick = 'insertComment(this, $user_id);'>";

The variables go into a JavaScript function:

function insertComment(input, user)
{
     //use input and user id to carry out tasks.
} 

The error message given is at the function call to 'insertComment()' in the onclick of the input. The error message looks like this:

SyntaxError: identifier starts immediately after numeric literal    

       insertComment(this, 9f60d869342a);

I have tried multiple quote and dot binations and have checked the other posts on StackOverFlow. They were all to no avail. Your help in resolving this error is greatly appreciated.

I am trying to pass in two variables to a JavaScript function: the input itself and the user id. I call the function using the onclick attribute of the input.

 echo "<input type = 'submit' class = 'replyButton' id = 'replyButton'
 value = 'reply' onclick = 'insertComment(this, $user_id);'>";

The variables go into a JavaScript function:

function insertComment(input, user)
{
     //use input and user id to carry out tasks.
} 

The error message given is at the function call to 'insertComment()' in the onclick of the input. The error message looks like this:

SyntaxError: identifier starts immediately after numeric literal    

       insertComment(this, 9f60d869342a);

I have tried multiple quote and dot binations and have checked the other posts on StackOverFlow. They were all to no avail. Your help in resolving this error is greatly appreciated.

• php
• javascript
• html
• web
• literals

• Possible duplicate of SyntaxError: identifier starts immediately after numeric literal in Firebug – Amir Commented Nov 23, 2015 at 5:57

1 Answer 1

you need to quote the user id

echo "<input type = 'submit' class = 'replyButton' id = 'replyButton'
 value = 'reply' onclick = 'insertComment(this, \"$user_id\");'>";