te')); return $arr; } /* 遍历用户所有主题 * @param $uid 用户ID * @param int $page 页数 * @param int $pagesize 每页记录条数 * @param bool $desc 排序方式 TRUE降序 FALSE升序 * @param string $key 返回的数组用那一列的值作为 key * @param array $col 查询哪些列 */ function thread_tid_find_by_uid($uid, $page = 1, $pagesize = 1000, $desc = TRUE, $key = 'tid', $col = array()) { if (empty($uid)) return array(); $orderby = TRUE == $desc ? -1 : 1; $arr = thread_tid__find($cond = array('uid' => $uid), array('tid' => $orderby), $page, $pagesize, $key, $col); return $arr; } // 遍历栏目下tid 支持数组 $fid = array(1,2,3) function thread_tid_find_by_fid($fid, $page = 1, $pagesize = 1000, $desc = TRUE) { if (empty($fid)) return array(); $orderby = TRUE == $desc ? -1 : 1; $arr = thread_tid__find($cond = array('fid' => $fid), array('tid' => $orderby), $page, $pagesize, 'tid', array('tid', 'verify_date')); return $arr; } function thread_tid_delete($tid) { if (empty($tid)) return FALSE; $r = thread_tid__delete(array('tid' => $tid)); return $r; } function thread_tid_count() { $n = thread_tid__count(); return $n; } // 统计用户主题数 大数量下严谨使用非主键统计 function thread_uid_count($uid) { $n = thread_tid__count(array('uid' => $uid)); return $n; } // 统计栏目主题数 大数量下严谨使用非主键统计 function thread_fid_count($fid) { $n = thread_tid__count(array('fid' => $fid)); return $n; } ?>mirth - How do I handle multiple repeated segments when creating an EDI 214 message via javascript? - Stack Overflow

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    mirth - How do I handle multiple repeated segments when creating an EDI 214 message via javascript? - Stack Overflow

    programmeradmin1浏览0评论

    We use mirth for our EDI transactions. I am creating a channel for an EDI214 for a customer. I'm not really sure how to handle multiple repeated segments in the destination transformer, in specific the L11 segments. They have multiple occurrences. From the database, we fill in these segments into mirth and map a 214 document. Here is an example of a message:

    `ISA00 00 ZZXXXX ZZXXXXXXX 2412191459U004010005206230P:

    GSQMANTCXXXXXX202412191459520623X004010

    ST214520623

    B10164951F896890181*XXXX

    L11XXXXX11

    L11DRYVANOT

    L11SOLOOT

    L11XXXXXXXX12

    L11172400000BM

    N1SHCurrent Location

    N4CATOOSAOK

    LX*1

    AT7X6NS**202412190659*LT

    MS1CATOOSAOK*US

    MS2ANTCNA

    L111QN

    L11172400000BM

    L114500586483OT

    L11BSWB17240001OT

    L11IIIOT

    L11LBOT

    L1123332OT

    L11HYPOCHLORITE SOLUTIONSOT

    LX*2

    AT7X6NS**202412190659*LT

    MS1MUSKOGEEOK*US

    MS2XXXXNA

    L1199QN

    L11172400000BM

    L114500586483OT

    L11BSWB17240001OT

    L11IIIOT

    L11LBOT

    L1123332OT

    L11TEST COMPANY NAMEOT

    SE34520623

    GE1520623

    IEA1000520623`

    At the moment, I have them filling in by index of occurence. I don't know if this will always work. Additionally, if a segment does not exist, I don't know if it will error. Am i going about this the right way?

    // L11 Segment
  tmp['L11'][0]['L11.01']['L11.01.1'] = tradingpartner //L11 BM
  tmp['L11'][0]['L11.02']['L11.02.1'] = "11"
  tmp['L11'][1]['L11.03']['L11.03.1'] = parsed_additional_information.equipment_type 
  tmp['L11'][1]['L11.04']['L11.04.1'] = "OT" // qualification code 
  tmp['L11'][2]['L11.05']['L11.05.1'] = parsed_additional_information.drivermessage 
  tmp['L11'][2]['L11.06']['L11.06.1'] = "OT" // number of units
  tmp['L11'][3]['L11.07']['L11.07.1'] = parsed_additional_information.billingaccount 
  tmp['L11'][3]['L11.08']['L11.08.1'] = "12" // code for billing account 
  if (parsed_additional_information.BM) {
    tmp['L11'][4]['L11.09']['L11.09.1'] = parsed_additional_information.BM
    tmp['L11'][4]['L11.10']['L11.10.1'] = "BM" // bill of lading number
  }
  tmp['N1'][0]['N1.02']['N1.02.1'] = shipment_msg.from_company_name;

  tmp['N3'][0]['N3.01']['N3.01.1'] = shipment_msg.from_address; 

  tmp['N4'][0]['N4.01']['N4.01.1'] = shipment_msg.from_city; 
  tmp['N4'][0]['N4.02']['N4.02.1'] = shipment_msg.from_state;
  tmp['N4'][0]['N4.03']['N4.03.1'] = shipment_msg.from_zip 

  tmp['N1'][1]['N1.02']['N1.02.1'] = shipment_msg.to_company_name; 
  tmp['N3'][1]['N3.01']['N3.01.1'] = shipment_msg.to_address; 

  tmp['N4'][1]['N4.01']['N4.01.1'] = shipment_msg.to_city; 
  tmp['N4'][1]['N4.02']['N4.02.1'] = shipment_msg.to_state
  tmp['N4'][1]['N4.03']['N4.03.1'] = shipment_msg.to_zip 
  tmp['LX'][0]['LX.01']['LX.01.1'] = "1"

    how do i handle the second occurence? just index it as well?

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