te')); return $arr; } /* 遍历用户所有主题 * @param $uid 用户ID * @param int $page 页数 * @param int $pagesize 每页记录条数 * @param bool $desc 排序方式 TRUE降序 FALSE升序 * @param string $key 返回的数组用那一列的值作为 key * @param array $col 查询哪些列 */ function thread_tid_find_by_uid($uid, $page = 1, $pagesize = 1000, $desc = TRUE, $key = 'tid', $col = array()) { if (empty($uid)) return array(); $orderby = TRUE == $desc ? -1 : 1; $arr = thread_tid__find($cond = array('uid' => $uid), array('tid' => $orderby), $page, $pagesize, $key, $col); return $arr; } // 遍历栏目下tid 支持数组 $fid = array(1,2,3) function thread_tid_find_by_fid($fid, $page = 1, $pagesize = 1000, $desc = TRUE) { if (empty($fid)) return array(); $orderby = TRUE == $desc ? -1 : 1; $arr = thread_tid__find($cond = array('fid' => $fid), array('tid' => $orderby), $page, $pagesize, 'tid', array('tid', 'verify_date')); return $arr; } function thread_tid_delete($tid) { if (empty($tid)) return FALSE; $r = thread_tid__delete(array('tid' => $tid)); return $r; } function thread_tid_count() { $n = thread_tid__count(); return $n; } // 统计用户主题数 大数量下严谨使用非主键统计 function thread_uid_count($uid) { $n = thread_tid__count(array('uid' => $uid)); return $n; } // 统计栏目主题数 大数量下严谨使用非主键统计 function thread_fid_count($fid) { $n = thread_tid__count(array('fid' => $fid)); return $n; } ?>javascript - Replace string that starts with specific character and ends with specific character in regular expression - Stack O

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    javascript - Replace string that starts with specific character and ends with specific character in regular expression - Stack O

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    I wanted to replace a string section that starts with a specific character and ends with specific character. At below, I demonstrate test case. 

    var reg = /pattern/gi;

var str = "asdfkadsf[xxxxx]bb";

var test = str.replace(reg,"") == "asdfkadsfbb"

console.log(test);

    I wanted to replace a string section that starts with a specific character and ends with specific character. At below, I demonstrate test case. 

    var reg = /pattern/gi;

var str = "asdfkadsf[xxxxx]bb";

var test = str.replace(reg,"") == "asdfkadsfbb"

console.log(test);
    • javascript
    • regex
    Share Improve this question edited Nov 7, 2017 at 14:44 Andrey Belykh 2,6544 gold badges34 silver badges49 bronze badges asked Apr 1, 2013 at 16:56 FreshbloodFreshblood 6,43110 gold badges61 silver badges98 bronze badges 5
    • In your example, you want to replace everything between the brackets? – Adam Plocher Commented Apr 1, 2013 at 16:57
    • Did you intend to replace [xxxxx] by b or was that a typo and the result should be asdfkadsfbb instead? – Jerry Commented Apr 1, 2013 at 16:58
    • @AdamPlocher Yes but including brackets too. – Freshblood Commented Apr 1, 2013 at 16:59
    • @jerry I removed b character now. – Freshblood Commented Apr 1, 2013 at 17:00
    • +1 for providing the test-case code. – MikeM Commented Apr 1, 2013 at 18:05
    Add a ment  | 

    2 Answers 2

    Reset to default 11

    This pattern should work for replace anything between brackets (including the brackets):

    var reg = /(\[.*?\])/gi;

var str = "asdfkadsf[xxxxx]bb";

var test = str.replace(reg,"") == "asdfkadsfbb"

    based on your example, this works:

    /\[.*]/gi
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